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3 years ago

A bag contains only green balls and red balls. A ball is taken at random from the bag. The probability

Mathematics

1 answer:

Andrew [12]3 years ago

7 0

Answer:

0step by step explanation because no blue in the bag

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Tommy has a pet monkey. Every day, his monkey eats 4 apples in the morning. The monkey also eats two bananas for every banana to

Kipish [7]

So, if tom eats 10 bananas in 10 days

than, monkey have eaten 40 apples and 20 bananas

hope this helped

8 0

3 years ago

In rhombus ABCD, find the measure of angle A. A) 142° B) 52° C) 38° D) 218°

pshichka [43]

38- b/c they are supplementary so 180-142=38

5 0

2 years ago

Read 2 more answers

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.

Arada [10]

Answer:

a) $0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

b) $n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

c) $n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

Part a

$\hat p=\frac{823}{1000}=0.823$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

Part c

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

5 0

2 years ago

Jamie has 8/10 of a candy bar leftover. He wants to split it into 1/3 pieces. How many 1/3 pieces. How many 1/3 pieces can he ma

valentina_108 [34]

If we change everything to the same denominator it will look like this. 24/30 and he wants to take 10/30. 24/30 - 10/30 is 14/30 so 14/30 - 10/30 is 4/30. *He can take 2 1/3 pieces*

8 0

3 years ago

Read 2 more answers

Express the radical using the imaginary unit, iii.<br> Express your answer in simplified form.

Reika [66]

$iii\implies i^3\implies i^2\cdot i\implies (-1)\cdot \sqrt{-1}\implies -\sqrt{-1}\implies -i$

4 0

11 months ago