Plant cells are rectangular or squarish in shape.
Plant cells have a large vacuole.
Answer is: <span> two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl</span>₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.
∆H° of the following reaction H₂(g) + I₂(g) → 2HI(g) is -3kJ/mol.
<h3>What is Bond Enthalpy? </h3>
The minimum amount of energy which is required to braak down or form the bonds in chemical reaction is known as bond enthalpy.
It can be calculated as:
∆Hrxn = sum of ∆H bond broken - sum. of ∆H of bond formed.
In order to Calculate ∆Hrxn for the given equation we have:
Bond energies in kJ/mol
- H—H = 436
- H—I = 295
- I—I = 151
Now, the given reaction is
H₂(g) + I₂(g) → 2HI(g)
Here, 1 mol of H₂ and 1 mole of I₂ breaks to form 2 moles of HI.
Therefore,
We know that,
∆Hrxn = B. E(H—H) + B. E(I—I) - 2B. E(H—I)
= 436 + 151 - 2× 295
= 436+ 151 - 590
∆Hrxn = -3kJ/mol.
Thus, from the above conclusion we can say that ∆Hrxn of the reaction H₂(g) + I₂(g) → 2HI(g) is -3kJ/mol.
learn more about Bond energy:
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Answer:
Monoatomic ions: Li⁺, Be²⁺, Cr²⁺, Pb²⁺, Cl⁻, O²⁻
Polyatomic ions: H₃O⁺, OH⁻, SO₄²⁻, Hg₂²⁺
Explanation:
Polyatomic ions have more than one atom. Monoatomic ions have only one atom.
Answer is: 158,5 km.
<span>1.87e3 m is 1870 m /1000 = 1,87 km.
</span><span>24 m is 24 / 1000 = 0,024 km.
</span><span>5.43e-1 km is 0,587 km.
</span><span>1.561e2 km is 156,1 km.
</span>summing: 1,87 km + 0,024 km + 0,587 km + 156,1 km = 158,5 km.
e3 means 10³ (10 · 10 · 10 = 1000).