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Drupady [299]
3 years ago
11

What is the reduction half-reaction for the following unbalanced redox equation?

Chemistry
2 answers:
bazaltina [42]3 years ago
5 0
First find the oxidation states of the various atoms: 
<span>in Cr2O2 2- Cr @ +1; In NH3 N @ +3; in CrO3 Cr @ +3, N2 N @ 0 </span>
<span>Note that N gained electrons, ie, was reduced; Cr was oxidized </span>
<span>Now there is a problem, because B has NH4+ which the problem did not, and is not balanced, showing e- in/out </span>
<span>B.NH4+ → N2 </span>

<span>Which of the following is an oxidation half-reaction? </span>
<span>A.Sn 2+ →Sn 4+ + 2e- </span>
<span>Sn lost electrons so it got oxidized</span>
Reptile [31]3 years ago
4 0
C. N2 → NH4+ would be the correct option
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3 years ago
What element has 80 protons, 81 neutrons, 79 electrons?
Mariana [72]

Answer:

The element will be ^{161}_{80}X

Explanation:

Given that,

Number of proton = 80

Number of neutron = 81

Number of electron = 79

We know that,

The atomic number is equal to the number of proton.

So, the atomic number is 80.

According to atomic number,

The element will be mercury.

We need to calculate the atomic mass

Using formula of atomic mass

atomic\ mass=atomic\ number+number\ of\ neutron

Put the value into the formula

atomic\ mass=80+81

atomic\ mass=161

We need to find the element

Using atomic mass and atomic number

atomic\ mass\ number A=161

atomic\ number Z=80

So, the element will be

^{A}_{Z}X

Put the value of A and Z

Hence, The element will be ^{161}_{80}X

5 0
3 years ago
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Len [333]

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the answer is d

Explanation:

but wusup shawty

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2. What will you change (the independent variable) in each test?
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