The question is incomplete, the complete question is; Describe the preparation of 2.00 L of 0.108 M BaCl2 from BaCl2.2H2O
Answer:
See explanation
Explanation:
First we must know the molar mass of the compound = 244.3 g/mol
Now we must calculate the number of moles of BaCl2.2H2O in the solution.
number of moles = concentration * volume = 0.108 M * 2.00 L = 0.216 moles
Now the mass of solid that we need to take can be obtained from;
number of moles = mass/molar mass
mass = number of moles * molar mass
mass = 0.216 moles * 244.3 g/mol
Mass = 52.8 g
Hence, we must weigh 52.8 g of BaCl2.2H2O accurately in a balance and dissolve it in 2 L of water to give 0.108 M solution of BaCl2.2H2O.
Answer:
( A ) Increases
Explanation:
More room, basically means more creatures. Like in a bedroom, you can only fit amount of people if its small the ocean is like that with depth.
Hopefully this makes sense???
The actual mass is 904.4g but with correct number of sig figs it’s 904g.
Answer: 4.5 x 10e-7
Explanation: 450 x 1e+9 = correct answer
Multiply amount of nanometers by 1e+9 to get the approximate result in meters.
