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3 years ago

7

Maya open a savings account that pays 3.5% annual interest compounded semiannually.If she deposited $2,000 into the account and

made no other deposits or withdrawals, how much money did she have in the account after one year?

1 answer:

dalvyx [7]3 years ago

4 0

That would be $2,070 because 3.5% of 2000 is 70

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Principal = 5300=5300 rupees

PSYCHO15rus [73]

Answer:

Using the formula:

$A=P+I$

where

A is the total amount

P is the principal

I is the Simple Interest

As per the statement:

Principal(P) = 5300 rupees.

rate of interest(r) = 6.5% = 0.065

Total amount(A) = 6678 rupees.

Then using above formula we have;

$6678 = 5300+I$

Subtract 5300 both sides we get;

$1378 = I$

or

$I = \$1378$

We have to find the time period.

Using formula of Simple interest:

$I = Prt$

where r is the rate of interest (in decimal)

here, r = 6.5% = 0.065

Substitute the given values top find t:

$1378 = 5300 \cdot 0.065 \cdot t$

⇒ $1378 = 344.5t$

Divide both sides by 344.5 we have;

$4 = t$

Therefore, the time period t in years is 4 years

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3 years ago

We know that side NM is parallel to side XZ. If we consider side NY the transversal for these parallel lines, we create angle pa

Likurg_2 [28]

See the picture attached.

We know:
NM // XZ
NY = transversal line
∠YXZ ≡ ∠YNM

1) <span>We know that ∠XYZ is congruent to ∠NYM by the reflexive property.</span>

The reflexive property states that any shape is congruent to itself.
∠NYM is just a different way to call ∠XYZ using different vertexes, but the sides composing the two angles are the same.
Hence, ∠XYZ ≡ <span>∠NYM</span> by the reflexive property.

2) Δ<span>XYZ is similar to ΔNYM by the AA (angle-angle) similarity theorem

The AA similarity theorem states that if two triangles have a pair of corresponding angles congruent, then the two triangles are similar.
Consider </span>Δ<span>XYZ and ΔNYM:
</span>∠YXZ ≡ <span>∠YNM
</span>∠XYZ ≡ ∠NYM
Hence, ΔXYZ is similar to ΔNYM by the AA similarity theorem.

8 0

3 years ago

Read 2 more answers

suppose that prices of a certain model of new homes are normally distributed with a mean of $150,000. use the 68-95-99.7 rule to

Lelechka [254]

152700 is answer. Try to do these problems on paper then you can see where you went wrong . also try to do the actual question

5 0

3 years ago

De dónde se obtienen los datos generales complementarios que se utilizan para calcular la razones de actividad

VARVARA [1.3K]

Answer:

En el departamento de ventas.

Explicación paso a paso:

Los datos generales complementarios se pueden obtener del departamento de ventas donde están presentes los datos sobre ventas y nos ayudan a calcular los ratios de actividad. El índice de actividad se puede calcular dividiendo las ventas de la empresa por sus activos totales. Este índice de actividad indica la eficiencia de una empresa mediante el uso de sus activos disponibles para producir ventas. El índice de actividad también se denomina "Índice de gestión de activos". Los datos de ventas son necesarios para el índice de actividad que puede estar disponible en el departamento de ventas.

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3 years ago

Arif's backyard is 24 by 37 meters. He wants to put a flower garden in the middle of the backyard, leaving a strip of grass of

Tpy6a [65]

Answer:

Length of the flower garden = 29 meters

Width of the flower garden = 16 meters

Step-by-step explanation:

I have also attached a diagram for your convenience

Now First let us see the data we are given with:

Arif's backyard length = 37 meters

Arif's backyard Width = 24 meters

Area that should be left with grass = 424 m^2

Now lets suppose the width of the stirp of grass be "a"

According the image the area of backyard will be:

Area ABCD = 24 x 37

Area ABCD = 888 m^2

The length LM will be = (37 -2a)

The Width LO will be = (24 -2a)

Area LMNO = (37 -2a) x (24 -2a)

Area LMNO = 888 -74a -48a +4a^2

Area LMNO = 4a^2 -122a + 888

Now in order the to calculate the area of the grass strip we must subtract the area LMNO from the total area ABCD and we already know that the areas the area of grass strip should be 424 m^2

hence, A = Area ABCD - Area LMNO

424 = 888 - (4a^2 -122a + 888)

424 = 888 - 4a^2 +122a - 888

424 = -4a^2 +122a

4a^2 -122a +424=0

(We can solve this quadratic equation by breaking the middle term method)

2(2x-53)(x-4) = 0

2(2x-53) = 0

2x -53 = 0

x = 53/2

x = 26.5 (Not Possible)

x-4 = 0

x = 4

Length of the flower garden = 37 -2(4)

Length of the flower garden = 29 meters

Width of the flower garden = 24 -2(4)

Width of the flower garden = 16 meters

4 0

3 years ago