Question

6. Two linear equations are shown in the graph.

Answer 1

Answer:

D.(3, 3)

Step-by-step explanation:

The equation of a straight line is given as:

y = mx + c;

where x, y are variables, m is the slope of the line, c is the y intercept.

From the graph, we can see that line 1 passes through (6,0) and (0,6).

The equation of line 1 is given as:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-0=\frac{6-0}{0-6} (x-6)\\\\y=-x + 6\ \ \ (1)$

Line 2 passes through (6, 5) and (0, 1)

The equation of line 2 is given as:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-5=\frac{1-5}{0-6} (x-6)\\\\y=\frac{2}{3}x + 1\ \ \ (2)$

To get the coordinates of the intersection of the two lines, we solve equation 1 and 2 simultaneously using a calculator. This gives:

x = 3, y = 3

Therefore the two lines meet at (3, 3)