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3 years ago

What creates the van allen belts

Chemistry

2 answers:

Pavlova-9 [17]3 years ago

4 0

Answer:

b. deflection of charged particles

Explanation:

The Van Allen Belt is a region where various atmospheric phenomena occur due to deflection of charged particles in the Earth's magnetic field, discovered in 1958 by James Van Allen, who designed a cosmic ray experiment embarked on the American explorer spacecraft Explorer 1, launched in January 2000. 1958. Van Allen's radiations do not occur, except for rare exceptions, at the poles, but in the equatorial region. These form two ring-shaped belts, centered on the equator. The innermost reaches between altitudes of one thousand and five thousand kilometers, its maximum intensity occurring on average at three thousand kilometers. It consists of highly energetic protons, which originate from the decay of neutrons produced when cosmic rays from outer space collide with atoms and molecules of the earth's atmosphere. Some of the neutrons are ejected out of the atmosphere and disintegrate into protons and electrons as they cross this region of the belt. These particles move in spiral trajectories along force lines of the earth's magnetic field.

Anna71 [15]3 years ago

3 0

Hello there.

What creates the van allen belts

b. deflection of charged particles

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Which equation represents a neutralization reaction?

Harrizon [31]

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Explanation:

HCI(aq) + KOH(aq) → KCI(aq) + H20(l)

Acid + base → Salt + Water.

The above is a neutralization reaction in which an acid, aqeous HCl reacts completely with an appropriate amount of a base, aqueous KOH to produce salt, aqueous KCl and water, liquid H2O only.

This is a neutralization reaction since, the hydrogen ion, H+, from the HCl is neutralized by the hydroxide ion, OH-, from the KOH to form the water molecule, H2O and salt, KCl only.

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2 years ago

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2 years ago

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2 years ago

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Answer:

A. Increasing the temperature will favor forward reaction and more CaCo3 formed.

B. More CaCo3 will be formed.

C. CaCo3 will decrease and more react ants formed.

D. Less CaCo3 will be formed.

E. Iridium is a catalyst so there is no effect

Explanation:

A. Temperature will increase because it's an endothermic reaction.

B. Adding Cao will favor forward reaction and more CaCo3 formed.

C. Removing methane, more react ants are formed and CaCo3 decreases.

D. Irridi is a catalyst so it has no effect on the CaCo3 but only speeds its rate of reaction.

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2 years ago

Calculate the molality of a solution that contains 51.2 g of naphthalene, C10H8, in 500 mL of carbon tetrachloride. The density

PtichkaEL [24]

Answer: The molality of naphthalene solution is 0.499 m

Explanation:

Density is defined as the ratio of mass and volume of a substance.

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$ ......(1)

Given values:

Volume of carbon tetrachloride = 500 mL

Density of carbon tetrachloride = 1.60 g/mL

Putting values in equation 1, we get:

$\text{Mass of carbon tetrachloride}=(1.60g/mL\times 500mL)=800g$

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molarity:

$\text{Molality of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent (in g)}}$ .....(2)

Given values:

Given mass of naphthalene = 51.2 g

Molar mass of naphthalene = 128.17 g/mol

Mass of solvent = 800 g

Putting values in equation 2, we get:

$\text{Molality of naphthalene}=\frac{51.2\times 1000}{128.17\times 800}\\\\\text{Molality of naphthalene}=0.499m$

Hence, the molality of naphthalene solution is 0.499 m

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2 years ago