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Olenka [21]
3 years ago
5

What is one difference between an electron and a neutron?

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer: Neutron has no charge, electron has a charge and mass. Neutron occurs inside the nucleus where electron is seen outside the nucleus.

Explanation:

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I need help
Liono4ka [1.6K]

Answer:

d and e - Sodium and antimony

Explanation:

The atomic numbers remain the same, while the mass numbers change (because neutrons are being added or taken away).

sodium has an atomic number of 19 and a mass number of 39 - in d, it has an atomic number of 19 but a mass number of 40. therefore, it is an isotope

antimony has an atomic number of 51 and a mass number of 121.60 - in e, it has an atomic number of 51, but a mass number of 123. therefore, it is an isotope

6 0
3 years ago
Why do heart diseas patient's eat oil instead of fat?​
7nadin3 [17]

Answer:

lube

Explanation:

8 0
3 years ago
Read 2 more answers
How many moles of hydrogen ions are formed in the ionization of 0.250 moles of H2SO4?
True [87]

Answer:

The ionization of 0.250 moles of H₂SO₄ will produce 0.5 moles of H⁺ (hydrogen ion)

Explanation:

From the ionization of H₂SO₄, we have

H₂SO₄ → 2H⁺ + SO₄²⁻

Hence, at 100% yield, one mole of H₂SO₄ produces two moles of H⁺ (hydrogen ion) and one mole of SO₄²⁻ (sulphate ion), therefore, 0.250 moles of H₂SO₄ will produce 2×0.250 moles of H⁺ (hydrogen ion) or 0.5 moles of H⁺ (hydrogen ion) and 0.25 moles of SO₄²⁻ (sulphate ion).

That is; 0.250·H₂SO₄ → 0.5·H⁺ + 0.250·SO₄²⁻.

4 0
3 years ago
The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?​
Natasha_Volkova [10]

Answer:

3.13%.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 0.15

Half life (t½) = 2 mins

Number of half-life (n) = 5

Fraction of sample remaining =.?

Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

NOTE: n is the number of half-life.

N = 1/2ⁿ × N₀

N = 1/2⁵ × 0.15

N = 1/32 × 0.15

N = 0.15/32

N = 4.69×10¯³

Therefore, 4.69×10¯³ is remaining after 5 half-life.

Finally, we shall the fraction of the sample remaining after 5 half-life as follow:

Original amount (N₀) = 0.15

Amount remaining (N) = 4.69×10¯³

Fraction remaining = N/N₀ × 100

Fraction remaining = 4.69×10¯³/0.15 × 100

Fraction remaining = 3.13%

3 0
3 years ago
Which of the following is false? a. an apoenzyme can catalyze its reaction without its cofactor b an organic cofactor can be cal
ozzi

Answer: Option (a) is the correct answer.

Explanation:

A protein part of an enzyme is known as an apoenzyme. An apoenzyme combines with a cofactor, it is known as holoenzyme.

Without a cofactor an apoenzyme cannot function as cofactor helps in the formation of an active enzyme system and provides a specific site on enzyme for the substrate.

Whereas a non-protein chemical compound or metal ion that helps in the activity of enzyme as a catalyst is known as a cofactor. A metal ion cofactor can be bound directly to the enzyme or to a coenzyme.

The organic non-protein molecules which bind to the protein molecule to form an active enzyme is known as a coenzyme. Coenzymes are small size molecules which help the enzymes to act as a catalyst.

Therefore, we can conclude that the statement an apoenzyme can catalyze its reaction without its cofactor, is false.

3 0
3 years ago
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