Answer:
Step-by-step explanation:
Given is a function as 
Equating to 0 we have equation
If the function f(x) has x intercepts then the solutions are real
Let us use remainder theorem and change of signs rule
f(0) = 1>0
f(-1) = -1+3+1=3
f(-2) = -32+6+1<0
This implies there is a real root between -1 and -2.
f(1) = -1
Since f(0) and f(1) have different signs, there exists a real root between 0 and 1.
f(2) = 32-6+1>0
Since f(1) and f(2) have different signs there exists a real root between 1 and 2.
Thus there are definitely three real solutions as
one between -1 and 0, one between 0 and 1, and third between 1 and 2.
First you have to find out how many guys you have-1.) 32-9=23, then you divide the number of men by the number of students-2.) 23÷32=0.718, so the answer is 0.7
They are similar by the SSS postulate<span />
Answer:
true for number 1 and for number 2 It is not thats the wrong answer the real answer is 13 because 10 11 12 13
Step-by-step explanation:
Answer:
d(t) = -20t -260
Step-by-step explanation:
We are given two points ...
(t, d) = (3, -320) and (8, -420)
The 2-point form of the equation of a line can be useful when 2 points are given.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
Substituting the given points, we have ...
d(t) = (-420 -(-320))/(8 -3)(t -3) -320
d(t) = -20(t -3) -320
d(t) = -20t -260
