1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alborosie
3 years ago
14

HELP PLEASE!!!

Physics
1 answer:
enyata [817]3 years ago
5 0

The power in watts is the energy in Joules used per second. This is:

P [W] = E[J] / t[s]

Solving for Energy:

E = P*t

We must convert the time to seconds knowing that 1 min = 60 s:

t = 6 min × 60 = 360 s

Finally:

E = P*t

E = 133 W * 360 s

E = 47880 J

<h2>The work of the runner is 47880 J</h2>
You might be interested in
Which best describes a nonmagnetic material?
Natali [406]
Material that is not attracted to metal

3 0
3 years ago
Read 2 more answers
an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per seco
Semenov [28]

Answer:

ac = 72 m/s²

Fc = 504 N

Explanation:

We can find the centripetal acceleration of the hammer by using the following formula:

a_c = \frac{v^2}{r}

where,

ac = centripetal acceleration = ?

v = constant speed = 12 m/s

r = radius = 2 m

Therefore,

a_c = \frac{(12\ m/s)^2}{2\ m}

<u>ac = 72 m/s²</u>

<u></u>

Now, the centripetal force applied by the athlete on the hammer will be:

F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)

<u>Fc = 504 N</u>

6 0
3 years ago
a snail takes 16 minutes 40 seconds to cover a distance of 1 m calculate the average speed of the swimmer​
matrenka [14]
The snail’s speed is 0.001042. Hope this helps!

8 0
3 years ago
Read 2 more answers
A ball with an initial velocity of 8.00 m/s rolls up a hill without slipping. (a) Treating the ball as a spherical shell, calcul
GrogVix [38]

Answer:

Part i)

h = 5.44 m

Part ii)

h = 3.16 m

Explanation:

Part i)

Since the ball is rolling so its total kinetic energy in this case will convert into gravitational potential energy

So we have

\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = mgh

here we know that for spherical shell and pure rolling conditions

v = R \omega

I = \frac{2}{3}mR^2

\frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{3}mR^2)(\frac{v^2}{R^2}) = mgh

\frac{5}{6}mv^2 = mgh

h = \frac{5v^2}{6g}

h = \frac{5(8^2)}{6(9.81)} = 5.44 m

Part b)

If ball is not rolling and just sliding over the hill then in that case

\frac{1}{2}mv^2 = mgh

h = \frac{v^2}{2g}

h = \frac{8^2}{2(9.81)} = 3.16 m

3 0
3 years ago
What is a normal force?
Flauer [41]
Is the component perpendicular to the surface on contact  of the  contact force  <span />
3 0
4 years ago
Other questions:
  • A surface weather map shows air circulation in a counterclockwise pattern. what does this represent? there isnt a picture btw
    9·2 answers
  • The maximum amount of static friction between this chair and the floor is 175 N. Which action would cause the chair to move to t
    9·1 answer
  • A group of tourists drives through a state park in Maine. While arguing about whether the animal they've just seen is an Elk or
    8·1 answer
  • A triply charged ion with velocity 7.00 × 10^6 m/s moves in a path of radius 36.0 cm in a magnetic field of 0.55 T in a mass spe
    11·1 answer
  • a 2.0 kg block on an incline at a 60.0 degree angle is held in equilibrium by a horizontal force, what is the magnitude of this
    14·2 answers
  • A light beam travels through a diamond (n=2.42) to pure water (n=1.33). The refracted ray will:
    9·1 answer
  • When thermal energy is added to an object what happens to the motion of the particles
    6·2 answers
  • Someone please help me with finding the resistance of these circuits! I've been asking for an hour now. I will give brainliest i
    14·1 answer
  • The flow of electricity in a certain path is called.
    5·1 answer
  • the asthenosphere is an important layer because it . 5) a) responds to forces by flowing as it is relatively strong b) responds
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!