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Alborosie
3 years ago
14

HELP PLEASE!!!

Physics
1 answer:
enyata [817]3 years ago
5 0

The power in watts is the energy in Joules used per second. This is:

P [W] = E[J] / t[s]

Solving for Energy:

E = P*t

We must convert the time to seconds knowing that 1 min = 60 s:

t = 6 min × 60 = 360 s

Finally:

E = P*t

E = 133 W * 360 s

E = 47880 J

<h2>The work of the runner is 47880 J</h2>
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An electric field of intensity 3.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
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Answer:

\varphi_1= 796.25 N m^2/C

\varphi_2= 0 N m^2/C

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Explanation:

From the question we are told that

Electric field of intensity E= 3.25 kN/C

Rectangle parameter Width W=0.350 m  Length L=0.700 m

Angle to the normal \angle=30.5 \textdegree

Generally the equation for Electric flux at parallel to the yz plane \varphi_1 is mathematically given by

\varphi_1=EA cos theta

\varphi_1=3.25* 10^3 N/C * ( 0.350)(0.700) cos 0

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Generally the equation for Electric flux at parallel to xy  plane \varphi_2 is mathematically given by

\varphi_2=EA cos theta

\varphi_2=3.25* 10^3 N/C * ( 0.350)(0.700) cos 90

\varphi_2= 0 N m^2/C

Generally the equation for Electric flux at angle 30 to x plane \varphi_3 is mathematically given by

\varphi_3=EA cos theta

\varphi_3=3.25* 10^3 N/C * ( 0.350)(0.700) cos 30.5

\varphi_3=686.072219  N m^2/C

\varphi_3=686.1  N m^2/C

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