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kvasek [131]
3 years ago
12

Write the equation in slope-intercept form. Then graph the line described by the equation?

Mathematics
1 answer:
hoa [83]3 years ago
8 0
2x+3y=6
3y=-2x+6
y=  -2/3x+2
*credit to Desmos graphing calc.

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Hi there!

Point-slope form: y-y_1=m(x-x_1) where <em>m</em> is the slope of the line and (x_1,y_1) is a given point

Given that the slope is -3/4, we can plug it into y-y_1=m(x-x_1) as <em>m</em>:

y-y_1=\displaystyle -\frac{3}{4}(x-x_1)

We can also plug in the given point (1,2):

y-2=\displaystyle -\frac{3}{4}(x-1)

Slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when the line crosses the y-axis)

To write the equation in slope-intercept form, isolate <em>y</em>:

y-2=\displaystyle -\frac{3}{4}(x-1)\\\\y=\displaystyle -\frac{3}{4}(x-1)+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{3}{4}+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{11}{4}

I hope this helps!

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