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3 years ago

What is 2 + 1 - 3 = 5 3 6

Mathematics

2 answers:

Paladinen [302]3 years ago

4 0

2 + 1 = 3
3 - 3 = 0
Hope this helped :)

weqwewe [10]3 years ago

3 0

2 because 5+3-6=2
2+1-3=then add 2+0

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Please help me out with this :)

yan [13]

Answer:

y = x - 5

Step-by-step explanation:

Given the equation

y = x + ?

We are being asked what value is added to x to give y

Consider the table, that is

x = 1 → y = - 4

x = 2 → y = - 3

x = 3 → y = - 2

x = 4 → y = - 1

x = 5 → y = 0

x = 6 → y = 1

In each case 5 is being subtracted from x to obtain y, that is

y = x - 5 ← equation relating x and y

6 0

3 years ago

Read 2 more answers

What is the polynomial -9+1/8x-7x^4+x^2-x^5 in standard form

Oduvanchick [21]

Answer:

-x^5 - 7x^4 + x^2 + (1/8)x - 9

Step-by-step explanation:

Rewrite the given -9+1/8x-7x^4+x^2-x^5 in descending order of the variable x:

-9+1/8x

-x^5 - 7x^4 + x^2 + (1/8)x - 9

7 0

3 years ago

Charla wants to determine the vertex of the function f(x) = x2 – 18x + 60 by changing the function into vertex form. Which state

7nadin3 [17]

Answer:

A. the x-coordinate of the vertex is greater than the y-coordinate.

Step-by-step explanation:

hope this helps

correct me if this is wrong

6 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

A charity sold 475 tickets show your work

sammy [17]

What? What work is supposed to be shown? That’s more like a statement

5 0

3 years ago

Read 2 more answers