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2 years ago

Write down the equation that could be a correct equation for linear regression prediction function?

Mathematics

1 answer:

user100 [1]2 years ago

6 0

If the question meant that we should write a linear prediction function ;

Answer:

y = bx + c

Step-by-step explanation:

The equation for a linear regression prediction function is stated in the form :

y = bx + c

Where ;

y = Predicted or dependent variable

b = slope Coefficient

c = The intercept value

x = predictor or independent variable

Therefore, the Linear function Given represents a simple linear model for one dependent variable, x

b : is the slope value of the equation, whuch represents a change in y per unit change in x

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What is the first derivative of r with respect to t (i.e., differentiate r with respect to t)? r = 5/(t2)Note: Use ^ to show exp

adelina 88 [10]

Answer:

The first derivative of $r(t) = 5\cdot t^{-2}$ (r(t)=5*t^{-2}) with respect to t is $r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3}).

Step-by-step explanation:

Let be $r(t) = \frac{5}{t^{2}}$ , which can be rewritten as $r(t) = 5\cdot t^{-2}$ . The rule of differentiation for a potential function multiplied by a constant is:

$\frac{d}{dt}(c \cdot t^{n}) = n\cdot c \cdot t^{n-1}$ , $\forall \,n\neq 0$

Then,

$r'(t) = (-2)\cdot 5\cdot t^{-3}$

$r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3})

The first derivative of $r(t) = 5\cdot t^{-2}$ (r(t)=5*t^{-2}) with respect to t is $r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3}).

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3 years ago

Is my answer correct?<br> Will give brainliest!!

Helen [10]

Yes your answer is correct

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