First find the slope of f(x).
m=(y2-y1)/(x2-x1)
m=(1-5)/(2-0)
m=-4/2
m=-2
y=-2x+b, using (2,1) we can solve for the y-intercept, "b"
1=-2(2)+b
1=-4+b
5=b
y=-2x+5
So f(x) has a y-intercept of 5
g(x)=6m+3
So g(x) has a y-intercept of 3
h(x)=3x+4
So h(x) has a y-intercept of 4
Then g(x) has the lowest y-intercept of just 3.
+3 and -18
The pair of integers are -3 and 6.
-3 + 6 = +3
-3 * 6 = -18
-14 and +24
The pair of integers are -2 and -12
-2 + -12 = -14
-2 * - 12 = +24
Let us assume the larger number = x
Let us assume the smaller number = y
Then
x + y = 3 3/4
x + y = 15/4
And
x/3 = (2y/3) + 1/2
x = [3 * (2y/3)] + (3/2)
= 2y + (3/2)
Now putting the value of x from the second equation to the first , we get
x + y = 15/4
2y + (3/2) + y = 15/4
3y = (15/4) - (3/2)
3y = (15 - 6)/4
3y * 4 = 9
12y = 9
y = 9/12
= 3/4
Now putting the value of y in the first equation, we get
x + y = 15/4
x + (3/4) = (15/4)
x = (15/4) - (3/4)
= (15 - 3)/4
= 12/4
= 3
So the value of x or the larger number is 3 and the value of y or the smaller number is 3/4.
It’s 13 and 15 you felllmeeyebebenr
Answer:
she purchased 6 first class tickets and 2 normal tickets
Step-by-step explanation:
