The distnace around a two dimensional shape
X = y + 11
2x + y = -2
2(y + 11) + y = -2
2y + 22 + y = -2
3y + 22 = -2
3y = -24
y = -8
x = y + 11
x = -8 + 11
x = 3
Solution set {3, -8} (C)
sin 45 = opp/hyp
sin 45 = 4 / y
y = 4/sin 45
y = 4 /((sqrt2)/2)=4* sqrt(2)
tan 45 =opp/adj
tan 45 = 4/(x-3)
1 = 4/(x-3)
x-3 = 4
x=7
B
Answer:
it's quadratic
Step-by-step explanation:
sorry i answered late but i hope this helps other people
