Answer:
Explanation:
<u>1) Rate law, at a given temperature:</u>
- Since all the data are obtained at the same temperature, the equilibrium constant is the same.
- Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:
r = K [A]ᵃ [B]ᵇ
<u>2) Use the data from the table</u>
- Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:
r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s
r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s
Divide r₂ by r₁: [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0
- Use the first and second set of data to find the exponent a:
r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s
r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s
Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]
2ᵃ = 2 ⇒ a = 1
<u>3) Write the rate law</u>
This means, that the rate is independent of reactant B and is of first order respect reactant A.
<u>4) Use any set of data to find K</u>
With the first set of data
- r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹
Result: the rate constant is K = 0.167 s⁻¹
Answer:
Cl is not a compound because compounds are made up of atoms from MORE than one element. Since Cl is a singular element is cannot be a compound
Explanation:
Just think of it as Compounds are always more than one elements are always Single
Answer:
im pretty sure its 1 mole of sugar
Explanation:
2.05 oz (58.45 g) of salt and 11.98 oz (342.3 g) of sugar
Answer: An example:
Measure the distance between the center of the spreading center (red) and the border between dark yellow and light green (65 Ma point) I measured 2 cm Since the scale on the map is 1 cm = 475 km, calculate the real distance that the plate has moved over the past 65 Ma 2 cm * 475 km/cm = 950 km = 95,000,000 cm = 9.5 * 107 cm Determine the length of time that the plate has been moving65 million years = 65,000,000 years = 6.5 * 107 yearsUse the above equation to calculate spreading rateR = d/t or R = 9.5 * 107 cm / 6.5 * 107 years = 1.46 cm/yr
Explanation:
The most stable conformation of
trans-1-tert-butyl-2-methylcyclohexane is the one in which both the
tert-butyl group and the methyl group are located near the equatorial position.
Trans conformation are usually stable at the equatorial position to avoid the
bulkyl group ( the tert-butyl group and methyl group) be together to reduce the
so called Steric hindrance.
