Answer:
We need 420 cal of heat
Explanation:
Step 1: Data given
Mass of the aluminium = 200.0 grams
Temperature rises with 10.0 °C
Specific heat of aluminium = 0.21 cal/g°C
Step 2: Calculate the amount of heat required
Q =m * c* ΔT
⇒with Q = the amount of heat required= TO BE DETERMINED
⇒with m = the mass of aluminium = 200.0 grams
⇒with c = the specific heat of aluminium = 0.21 cal/g°C
⇒with ΔT = the change of temperature = 10.0°C
Q = 200.0 grams * 0.21 cal/g°C * 10.0 °C
Q = 420 cal
We need 420 cal of heat (option 2 is correct)
Answer:
1 to 696
The expansion ratio of liquefied and cryogenic from the boiling point to ambient is: nitrogen 1 to 696. liquid helium 1 to 757. argon 1 to 847.
Explanation:
Answer:
c cells
Explanation:
learned that in 7th grade
Displacement, usually the method that is used to measure the volume of an irregularly shaped object.
