All categories

2 years ago

How many grams are present in 0.26 moles of methane

Chemistry

1 answer:

zheka24 [161]2 years ago

5 0

Answer:

4.17 g

Explanation:

Moles and Mass are related as,

Mole = Mass / M.Mass

Or,

Mass = Mole × M.Mass

M.Mass of Methane = 16.04 g/mol

Putting values,

Mass = 0.26 mol × 16.04 g/mol

Mass = 4.17 g

You might be interested in

In the reaction K2CrO4 (aq) + PbCl2 (aq) 2KCl (aq) + PbCrO4(s), how many grams of PbCrO4 will precipitate out from the reaction

likoan [24]

We first calculate the number of moles of K2CrO4 by multiplying the volume with the molarity.
n = (25/1000) x (3 M) = 0.075 mol K2CrO4
Then, from the balanced chemical equation, each mole of K2CrO4 will produce 1 mole PbCrO4 with molar mass of 323.2 g/mol.
(0.075 mol K2CrO4)(1 mol PbCrO4/1 mol K2CrO4) x (323.2 g/mol)
= 24.24 grams PbCrO4

3 0

3 years ago

Read 2 more answers

what is the electrons, valence electrons, and electron shells number please answer all 3 questions (look at the picture)

MariettaO [177]

In picture one, there are four electrons, one valance electrons and two shells, in image two there are three electrons, one valance electrons and two shells whereas there are 13 electrons, three valance electrons and three shells.

<h3>What is Electrons, Valence Electrons, and Electron Shells Numbers?</h3>

<u>Electrons</u>:

An electron is a negatively charged particle which can be either bounded with to an atom. Electrons belong to the first generation of the lepton particle family, and are generally thought to be elementary particles because they have no known components or substructure.

<u>Valence Electrons:</u>

Valence electrons are those electrons which are present in outermost shell or in valence shell or energy level of an atom. For example, oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.

<u>Electron Shells Numbers</u>:

Each shell can contain only a fixed number of electrons: the first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on.

So we can conclude that In picture one, there are four electrons, one valance electrons and two shells, in image two there are three electrons, one valance electrons and two shells whereas there are 13 electrons, three valance electrons and three shells.

Learn more about Valence Electrons here: brainly.com/question/371590

#SPJ1

4 0

1 year ago

The following data was collected for the formation of ammonia (NH3) based on the following overall reaction: N2 + 3H2 = 2NH3 N2

notsponge [240]

Answer : The unit for the rate constant in the rate law for the formation of ammonia is, $M^{-2}min^{-1}$

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$N_2+3H_2\rightarrow 2NH_3$

Rate law expression for the reaction:

$\text{Rate}=k[N_2]^a[H_2]^b$

where,

a = order with respect to $N_2$

b = order with respect to $H_2$

Expression for rate law for first observation:

$0.0021=k(0.10)^a(0.10)^b$ ....(1)

Expression for rate law for second observation:

$0.0084=k(0.10)^a(0.20)^b$ ....(2)

Expression for rate law for third observation:

$0.0672=k(0.20)^a(0.40)^b$ ....(3)

Dividing 2 by 1, we get:

$\frac{0.0084}{0.0021}=\frac{k(0.10)^a(0.20)^b}{k(0.10)^a(0.10)^b}\\\\4=2^b\\b=2$

Dividing 3 by 1 and also put value of b, we get:

$\frac{0.0672}{0.0021}=\frac{k(0.20)^a(0.40)^2}{k(0.10)^a(0.10)^2}\\\\2=2^a\\a=1$

Thus, the rate law becomes:

$\text{Rate}=k[N_2]^a[H_2]^b$

$\text{Rate}=k[N_2]^1[H_2]^2$

Now, calculating the value of 'k' by using any expression.

$0.0021=k(0.10)^1(0.10)^2$

$k=2.1M^{-2}min^{-1}$

The value of the rate constant 'k' for this reaction is $2.1M^{-2}min^{-1}$

That means, the unit for the rate constant in the rate law for the formation of ammonia is, $M^{-2}min^{-1}$

7 0

4 years ago

Select all that apply. The electron configurations of some elements are given. Based on the electron configurations which elemen

erma4kov [3.2K]

Answer:

correct option: A and D

Explanation:

generally element from d block can for ion with multiple charge and having incomplete outershell means element do not have fullfiled or half filed orbital because in these case it takes more energy to remove valence shell electron.

8 0

3 years ago

Nata [24]

Oregon trail would be the best answer

8 0

4 years ago

Read 2 more answers

How many grams are present in 0.26 moles of methane ￼

How many grams are present in 0.26 moles of methane