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2 years ago

How many grams are present in 0.26 moles of methane

Chemistry

1 answer:

zheka24 [161]2 years ago

5 0

Answer:

4.17 g

Explanation:

Moles and Mass are related as,

Mole = Mass / M.Mass

Or,

Mass = Mole × M.Mass

M.Mass of Methane = 16.04 g/mol

Putting values,

Mass = 0.26 mol × 16.04 g/mol

Mass = 4.17 g

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1. If you have 5g of pennies how many dozen pennies do you have?

likoan [24]

Answer:

15.69 dozen

Explanation:

Mass of penny = 5 g

Dozens of penny =..?

Next, we shall convert 5 g to gross. This can be obtained as follow:

3824 g = 1000 gross

Therefore,

5 g = 5 g × 1000 gross / 3824 g

5 g = 1.3075 gross

Thus, 5 g is equivalent to 1.3075 gross.

Finally, we convert 1.3075 gross to dozen. This can be obtained as follow:

1 gross = 12 dozen

Therefore,

1.3075 gross = 1.3075 gross × 12 dozen / 1 gross

1.3075 gross = 15.69 dozen

Thus, 5 g of penny is equivalent to 15.69 dozen

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How many grams of drug powder would you need to weigh to prepare 32ml of a suspension that should have a strength of 20mg/ml?

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RATE LAW QUESTION !

vivado [14]

In general, we have this rate law express.:

$\mathrm{Rate} = k \cdot [A]^x [B]^y$
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation $\Delta \mathrm{Rate} = \Delta [B]^y$

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To this point, $\mathrm{Rate} = k \cdot [A]^x [B]^1$

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for $\Delta \mathrm{Rate} = \Delta [A]^x$

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(NH4)2CO3à NH3 + CO2 + H2O For this unbalanced chemical equation, what is the coefficient for carbon dioxide when the equation i

nasty-shy [4]

Answer:

The answer to your question is the letter A. 1

Explanation:

Data

Chemical reaction

(NH₄)₂CO₃ ⇒ NH₃ + CO₂ + H₂O

Reactants Elements Products

2 Nitrogen 1

1 Carbon 1

8 Hydrogen 5

3 Oxygen 3

This reaction is unbalanced

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Now, the reaction is balanced,

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How many grams are present in 0.26 moles of methane ￼

How many grams are present in 0.26 moles of methane