Answer: the answer is 374.061
Answer: 21 Feet Wide
Step-by-step explanation: 7ft x 3ft = 21ft wide
First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
T=650mi(hr/50mi)=13 hr
t-1=12 hr
12=650/(50+v) multiply both sides by 50+v
600+12v=650 subtract 600 from both sides
12v=50 divide both sides by 12
v=25/6 mph
v≈4.17mph
Answer:
0.229
Step-by-step explanation:
Given that the difference between the two sample means follows anormal distribution with a mean of11.00 and standard deviation equal to1.4387
A statistician is interested in the effectiveness of a weight-loss supplement. She randomly selects two independent samples. Individuals in the first sample of size n1 = 24 take the weight-loss supplement. Individuals in the second sample of size n2 = 21 take a placebo. Individuals in both samples follow identical exercise and diet programs. At the end of the study, the statistician measures the weight loss (in percent) of each participant.
We find that mean difference actual = 13-2 = 11
Probability that difference >12 =P(Z>
)
=P(Z>0.742)=.0.229
