A standing wave with a fundamental frequency 1.25x10 2 Hz is set up on a string of length 0.750 meters. What is the frequency of
the third harmonic?
1 answer:
Answer:
<em>500Hertz</em>
Explanation:
Given the fundamental frequency of the string given as 1.25x10²Hz
Harmonics are integral multiples of the fundamental frequency.
In strings, the third harmonic F3 is expressed in terms of the fundamental frequency expressed as;
F3 = 4F0
F0 is the fundamental frequency;
Given
F0 = 1.25x10²Hz
F3 = 4(1.25x10²)
F3 = 4(125)
F3 = 500Hz
<em>Hence the frequency of the third harmonic is 500Hertz</em>
<em></em>
You might be interested in
Answer:
24cm/s
Explanation:
A=L*w
A'=L'*w'
L=13
w=5
L'=4
w'=6
A=?
A'=?
A=L*w
A=13*5
A=65
A'=L'*w'
A'=4*6
A'=24
*the given lengths are just to throw you off*
Answer:
I know 1, that is in the case of a burning of a candle.
Explanation:
Answer:
f=ma
f=280N
m=40kg
a=?
280=40a
a=280/40
a=70N/kg
Explanation:
It is known that relation between torque and angular acceleration is as follows.

and, I = 
So, 
= 4 


So, 
= 1 
as 
=
Hence, 

Thus, we can conclude that the new rotation is
times that of the first rotation rate.
I think the correct answer is C