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3 years ago

Two students used different methods to measure the length of their model bridge

Mathematics

1 answer:

Oduvanchick [21]3 years ago

3 0

Answer:

Two students used different methods to measure the length of their model bridge

project. One student measured the bridge length in feet using 11n−2.9. The second

student measured the bridge length in feet using 5n + 6.4 What is the value of n if

the two measurements are equal?

Step-by-step explanation:

Two students used different methods to measure the length of their model bridge

project. One student measured the bridge length in feet using 11n−2.9. The second

student measured the bridge length in feet using 5n + 6.4 What is the value of n if

the two measurements are equal?

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Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?

Nutka1998 [239]

Answer:

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}$

${\dashrightarrow \sf{Principle = Rs.30000}}$
${\dashrightarrow \sf {Time = 4 \: years}}$
$\dashrightarrow \sf{Rate = 30\%}$
$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}$

$\dashrightarrow{\sf{Simple \: Interest }}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}$

$\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}$

Where

$\dashrightarrow{\sf{S.I = Simple \: Interest }}$
${\dashrightarrow{\sf{P = Principle }}}$
${\dashrightarrow{\sf{ R = Rate }}}$
${\dashrightarrow{\sf{T = Time}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{P \times R \times T}{100}}}}}}$

Substituting the values

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 120}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{3600000}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\cancel{\dfrac{3600000}{100}}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{Rs.36000}}}}}$

${\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}$

Henceforth,The Simple Interest is Rs.36000..

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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3 years ago

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a deli sells a sandwich spread for $6.40 per pound. How much do you have to pay for 24 ounces of the spread. (hint: 16 ounces in

ehidna [41]

24 ounces = 1,5pound
1pound= 6,40$
1,5pound=???
you do the math :):)

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3 years ago

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Find the gradient of the line segment between the points (0,2) and (-2,10).

Tasya [4]

Answer:

-4

Step-by-step explanation:

Find the gradient of the line segment between the points (0,2) and (-2,10).

Given data

x1= 0

x2= -2

y1= 2

y2=10

The expression for the gradient is given as

M= y2-y1/x2-x1

substitute

M= 10-2/-2-0

M= 8/-2

m= -4

Hence the gradient is -4

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3 years ago

What is the value of a? Blank units

Damm [24]

Answer:

289

a^2 x b^2 = c^2

a = 8 b= 15 c = s

64 + 225 = 289

square root 289 = 17

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3 years ago

What is the independent and dependent variable in this situation?

lord [1]

Cid Sam is a way to remember
C -control S - SAME (keep the same)

I -independent A- alter

D-depend M- measure

independent- number of downloads
Dependant - money spent

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