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Phoenix [80]
3 years ago
6

Multiply (x+2y)(x^2-xy+3y)

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

-2xy^2+x^2y+x^3+6y^2+3xy

Step-by-step explanation:

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If the animal is in the woods on one observation, then it is four times as likely to be in the woods as the meadows on the next
kvv77 [185]
My solution to the problem is as follows:

<span>day 1: 1 
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Therefore, <span>the probability that the animal is in the woods on fourth observation would be 0.4385.

I hope my answer has come to your help. God bless and have a nice day ahead!
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4 0
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