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inna [77]
3 years ago
6

Triangles ABC and DEF similar

Mathematics
1 answer:
Anarel [89]3 years ago
4 0

Answer:

DE = 4 1/2

EF = 3 3/4

Step-by-step explanation:

AB/AC = DE/DF

6/4 = DE/3

cross-multiply:

4DE = 18

DE = 18/4 or 4 1/2

AB/BC = DE/EF

6/5 = 4.5/EF

cross-multiply:

6EF = 22.5

EF = 3.75

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Qual o valor da soma dos monômios 10xm - 8mx + 6xm - 13xm?
soldi70 [24.7K]

Answer:

The value of given expression = - 5mx

Step-by-step explanation:

Given expression;

10xm - 8mx + 6xm - 13xm

Find:

The value of given expression

Computation:

⇒ 10xm - 8mx + 6xm - 13xm

Step 1 ;

Rearrange expression;

⇒ 10mx - 8mx + 6mx - 13mx

Step 2 ;

Adding all terms

⇒ 10mx + 6mx - 8mx - 13mx

Step 3 :

Subtract term

⇒ 16mx - 21mx

⇒ -5mx

The value of given expression = - 5mx

8 0
3 years ago
PLEASE HELP ANSWER THIS ASAP!!! :)
PilotLPTM [1.2K]

Answer:

C, 42 degrees

Step-by-step explanation:

Considering  angle BAD is 60 degrees, that makes angle BCD also 60 degrees. Since parallelograms have 360 degrees in total, we're still missing 240 degrees. Since angles BAD and BCD are congruent (equal), that means that angles ABC and ADC also have to be congruent. To find their angles, we do 240 divided by 2, which equals 120. Now that we know all of the angles, lets focus on angle ADC. Since angle 1 has been given to us, all we need to do is subtract 78 from 120 which turns out to be 42 degrees, which is the answer.

5 0
3 years ago
What shows how many molecules there are of a chemical formula? ​
olga nikolaevna [1]

Answer:

no of moles = mass / molar mass

1 mole = 6.02 *10^23 molecules

I don't know if that helped

5 0
3 years ago
You can use the _______ of a quadratic equation to determine the number and type of solutions
Dennis_Churaev [7]

Answer: Discriminant.


Step-by-step explanation:

1. The quadratic formula is:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. And the discriminant is inside the square root:

b^{2}-4ac

2. Then, if the discriminant is negative, the quadratic equation does not have real solutions, it has two imaginary solutions. If the discriminant is zero the quadratic has one solution. If the discriminant is positive, the quadratic equation has two distinct solutions.


7 0
3 years ago
Find constants p and q such that x^4-2x^3-x^2+2x+10=(x^2+px+5)(x^2+qx+2)
likoan [24]

Answer:

p = -4 q = 2

Step-by-step explanation:

  1. Expand the brackets ( yes the entire thing).
  2. group together the values with same co-effiecients; like (q+p)x^3 etc etc.
  3. equate the co-effiecients on the left hand side to the now grouped ones on the right, for example [x^3]: -2x^3= (q+p)x^3, the x^3 cancels and ull get an equation only in terms of p and q. do the same for [x] and ull get an equation with only q, solve this and get the value for q [q = 2].
  4. sub in this value for the [x^3] equation and ull get an answer for p [p= -4].

hope my explanation is understandable lol

7 0
3 years ago
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