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Charra [1.4K]
3 years ago
5

Qual o valor da soma dos monômios 10xm - 8mx + 6xm - 13xm?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

The value of given expression = - 5mx

Step-by-step explanation:

Given expression;

10xm - 8mx + 6xm - 13xm

Find:

The value of given expression

Computation:

⇒ 10xm - 8mx + 6xm - 13xm

Step 1 ;

Rearrange expression;

⇒ 10mx - 8mx + 6mx - 13mx

Step 2 ;

Adding all terms

⇒ 10mx + 6mx - 8mx - 13mx

Step 3 :

Subtract term

⇒ 16mx - 21mx

⇒ -5mx

The value of given expression = - 5mx

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Julie made identical necklaces out of shell she collected at the beach all together she we use 10 Brown shells 15 black shells a
Lelu [443]

Answer:

Therefore the number of brown shells in each necklace was  = 2 brown shells.

Step-by-step explanation:

If Julie made identical necklaces then we can say that number of each different colored shells were equally distributed among the necklaces.

So we can say that to find the number of necklaces we have to find the GCD (greatest common denominator) of the different colored shells.

Therefore the GCD of 10, 15 and 20 is 5.

Therefore Julia made 5 necklaces.

Therefore the number of brown shells in each necklace was = \frac{10}{5} = 2 shells.

4 0
4 years ago
On a car trip Sam drove m miles Kara drove twice as many miles as Sam and Darin drove 20 fewer miles than Kara in terms of m man
frutty [35]

Answer:

Darin drove '2m - 20' miles.

Step-by-step explanation:

We are given that Sam drove 'm' no. of miles.

As, it is also given that Kara drove twice as many miles as Sam. Therefore we get that Kara drove '2m' no. of miles.

Now, it is given that Darin drove 20 miles fewer than Kara .i.e. Darin drove '2m - 20' no. of miles.

Hence, in terms of m, Darin drove '2m - 20' miles.

5 0
3 years ago
What is the square root 6n carried to the power of 2/3 in radical form
BaLLatris [955]

Answer: \sqrt[3]{6n}

Step-by-step explanation:

We have the following expression:

(\sqrt{6n})^{\frac{2}{3}}

Which can be written as follows:

((6n)^{\frac{1}{2}})^{\frac{2}{3}}

Multiplying the exponents:

(6n)^{\frac{1}{3}}

Writing in radical form we finally have the result:

\sqrt[3]{6n}

7 0
3 years ago
Simplify <br> 14z+12y3+10y3+7y3
Alona [7]

Answer:

14z+29y^3

Step-by-step explanation:

14z+12y^3+10y^3+7y^3

Combine like terms

14z+29y^3

4 0
3 years ago
Read 2 more answers
Help for question 7 please
scoray [572]
◆ COMPLEX NUMBERS ◆

given \: expression \: is \: - \\ \\ - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + \sqrt{ - 9} \\ \\ we \: know \: that \: , \: \\ i = \sqrt{ - 1} \\ \\ {i}^{2} = - 1 \\ \\ {i}^{3 } = - i \\ \\ {i}^{4} = 1 \\ \\ \\ - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + \sqrt{9} i \\ = - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + 3i \\ \\ using \: the \: above \: properties \: of \: iota \: (i) \\ \\ = - 3(1) + 2( - i) + 2( - 1) + 3i \\ \\ = - 3 - 2i - 2 + 3i \\ \\ = (- 5 + i) \: \: \: ans.
7 0
3 years ago
Read 2 more answers
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