C= chair cost
t= table cost
Create two equations with the given information. Solve for one variable in equation one. Substitute that answer in equation two. Then you can solve for the needed information.
3c+2t=$18
5c+6t=$48
3c+2t=18
Subtract 2c from both sides
3c=18-2t
Divide both sides by 3
c=(18-2t)/3
Substitute the value for c in equation two:
5c+6t=$48
5((18-2t)/3)+6t=48
(90-10t)/3+6t=48
Multiply everything by 3 to eliminate fraction
(3)((90-10t)/3)+(3)(6t)=(3)(48)
90-10t+18t=144
90+8t=144
Subtract 90 from both sides
8t=54
Divide both sides by 8
t=$6.75 cost for table
Substitute the t value to solve for c:
3c+2t=18
3c+2(6.75)=18
3c+13.50=18
3c=4.50
c=$1.50 chair cost
Check:
5c+6t=$48
5(1.50)+6(6.75)=48
7.50+40.50=48
48=48
Hope this helps! :) If it does, please mark as brainliest.
C(-8,2) and M(0,0) , since M is at the origin. Let x₁ and y₁ be the
coordinates of S →s(x₁ , y₁)
C(-8,2) and S(x₁ , y₁)
The coordinates of M, the midpoint of CS are M(x₂ , y₂)
a) x₂ = (-8 + x₁)/2 , but x₂ = 0, then :
0 = -4+x₁/2 and x₁ = 8
b) y₂ = (2+y₁)/2 , but y₂ = o, then:
0 = 2+ y₁/2 and y₂ = -2
Then the coordinates of S are S(8 , -2)
Answer:
Step 1 (IM AM NOT SURE NOT MY FAULT IF ITS WRONG)
Step-by-step explanation:
Answer:
Length =
= 5/2 inches or 2 1/2 inches
Step-by-step explanation:
Lin lines the bottom of her first pan with aluminum foil. The area of the rectangular piece of foil 11 1 4 is square inches. Its length is 4 1 2 inches. What is the width of the foil? Explain your reasoning.
Area of rectangle = Length × Width
Widths = Area/Length
The area of the rectangular piece of foil 11 1/4 is square inches.
Its length is 4 1 /2 inches.
Hence:
Length = 11 1/4 /4 1/2
= 45/4 ÷ 9/2
= 45/4 × 2/9
= 5/2 inches
= 2 1/2 inches
