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Natali5045456 [20]
3 years ago
12

Lin lines the bottom of her first pan with aluminum foil. The area of the rectangular piece of foil 11 1 4 is square inches. Its

length is 4 1 2 inches. What is the width of the foil? Explain your reasoning.
Mathematics
1 answer:
prisoha [69]3 years ago
6 0

Answer:

Length =

= 5/2 inches or 2 1/2 inches

Step-by-step explanation:

Lin lines the bottom of her first pan with aluminum foil. The area of the rectangular piece of foil 11 1 4 is square inches. Its length is 4 1 2 inches. What is the width of the foil? Explain your reasoning.

Area of rectangle = Length × Width

Widths = Area/Length

The area of the rectangular piece of foil 11 1/4 is square inches.

Its length is 4 1 /2 inches.

Hence:

Length = 11 1/4 /4 1/2

= 45/4 ÷ 9/2

= 45/4 × 2/9

= 5/2 inches

= 2 1/2 inches

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Answer:

c. 441ft^2

Step-by-step explanation:

Area is height times length and since it's a square, safe to say that the sides are equal in length. So square root both of the given areas of the 2 square:

\sqrt{841} = 29

\sqrt{400} = 20

Now u have side b and c of the triangle, it's a right triangle so use the Pythagorean theorem a^2 + b^2 = c^2

a^2 + b^2 = c^2

a^2 + 20^2 = 29^2

a^2 + 400 = 841

subtract 4 from both sides

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square root both sides

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Now the side a of the triangle is also a side of the small square therefore

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Step-by-step explanation:

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svlad2 [7]

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