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riadik2000 [5.3K]
3 years ago
15

Can someone please help me with numbers 23 and 24 it is easy

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
8 0

ok so I am no expert (Actually i am it says it on my profile) but the answer is 69/5555*^ I hope that this helps you and if it was so easy then why can't ya do it buddy! lol jkjkjkjk

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6 and 186 its divison i dont know division<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormula1" title="\sqrt{x
fiasKO [112]

Answer:

31

Step-by-step explanation:

u divide 186 by 6. u divide by pretty much seeing how many times 6 can go into 186.

8 0
2 years ago
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Based on the pattern, what are the next two terms of the sequence?<br> 2, 5, 8, 11, . . .?
Ksenya-84 [330]

Answer:

2, 5, 8, 11, 14, 17

Step-by-step explanation:

rule = +3

4 0
3 years ago
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Los Angeles Airport bears 140 degrees from San Francisco Airport and is 540 km away. A pilot is planning a direct flight from Sa
Roman55 [17]
Create a triangle starting with the length of 540 coming out of SF to LA bearing 140.
This looks like it leaves SF in IV quadrant and enters LA in II quadrant. The wind will take the plane more to the east (right).  Therefore the pilot must aim to the west (left) in order for the wind to push it to the intended destination of LA. The second side of the triangle should come out of LA from the II quadrant bearing 290.  The length of this side is 60t (60 km/h * t = time flying).  The third side of the triangle connects the first two.  There for it comes out of SF at some unknown angle > 140 and connects with the 60t side.  The length of this third leg is 640t. (640 km/h * t = time flying).  The angle between the 540 side and the 60t side is 30.  This is found because the 540 side enters LA in 2nd quadrant as 130 angle .  The 60t side enters LA in 2nd quadrant as 160 angle.  Using law of sin's: sin 30/640t = sin x/60t.  The t's cancel and you are left with sin x = 3/64.  When solving for the angle x you get x = 2.6867 degrees.  Adding this to the bearing of 140, the compass bearing should be 142.6867 or 142.7 degrees.  To find the value of t, you use the law of sin's to get sin 30/640t = (sin (180 - 30 - 2.6867))/540.  Solving for t gives you: t = .7811.  This is in hours.  To convert to minutes multiply by 60 to get t = 46.87 minutes.  Add this to the 2pm departure time to get 2:47 pm arrival time.
8 0
3 years ago
Please help this is very important
alexandr1967 [171]

Answer:

Here's what I get.

Step-by-step explanation:

1. Rotate 180° about origin

The formula for rotation of a point (x,y) by an angle θ about the origin is  

x' = xcosθ  -  ysinθ

y' = ycosθ + xsinθ

If θ = 180°, sinθ = 0 and cosθ = -1, and the formula becomes

x' =   -x

y' =  -y

The rule is then (x, y) ⟶ (-x, -y).

H: (-3, -5) ⟶ (3, 5)

J: (-5, -3) ⟶ (5, 3)

Q: (0, -1) ⟶ (0, 1)  

The vertices of H'J'Q' are (3, 5), (5, 3), and (0, 1).

2. Rotation 90° counterclockwise about origin

cos90°  = 0 and sin90° = 1

x' = xcos90°  -  ysin90° = -y

y' = ycos90° + xsin90° =  x

The rule is then (x, y) ⟶ (-y, x).

B: (4, 5) ⟶ (-5, 4)

L: (5, 0) ⟶ (0, 5)

S: (2, 2) ⟶ (-2, 2)  

The vertices of B'L'S' are (-5, 4), (0, 5), and (-2, 2).

3. Rotation 90° clockwise about origin

cos(-90°) = 0 and sin(-90°) = -1

x' = xcos(-90°)  -  ysin(-90°) =  y

y' = ycos(-90°) + xsin(-90°) =  -x

The rule is then (x, y) ⟶ (y, -x).

F: (1, -5) ⟶ (-5, -1)

H: (-2, -3) ⟶ (-3, 2)

U: (-4, -5) ⟶ (-5, 4)  

The vertices of F'H'U' are (-5, -1), (-3, -2), and (-5, 4).

4. Rotate 180° about origin

The rule is (x, y) ⟶ (-x, -y).

J: (1, -1) ⟶ (-1, 1)

V: (2, 0) ⟶ (-2, 0)

Y: (5, -3) ⟶ (-5, 3)

R: (4, -3) ⟶ (-4, 3)  

The vertices of J'V'Y'R' are (-1, 1), (-2, 0), (-5, 3), and (-4, 3).

The figures below show your shapes before and after the rotations.

7 0
3 years ago
How do you do this math 18-0.4<br> in long subtraction
Gwar [14]
 18.0                  1
-  0.4             17.0
_____           - 0.4
------->           ____
                     17.6
5 0
3 years ago
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