Question

A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acceleration of the crate after it begins to move

Answer 1

The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

Mass (m) = 50 Kg

Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

Frictional force (Fբ) =?

Fբ = μN

Fբ = 0.15 × 500

Fբ = 75 N

• Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

Net force (Fₙ) =?

Fₙ = F – Fբ

Fₙ = 100 – 75

Fₙ = 25 N

• Finally, we shall determine the acceleration of the crate

Mass (m) = 50 Kg

Net force (Fₙ) = 25 N

Acceleration (a) =?

a = Fₙ / m

a = 25 / 50

a = 0.5 m/s²

Therefore, the acceleration of the crate is 0.5 m/s²

Learn more on friction: brainly.com/question/364384