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shusha [124]
2 years ago
11

A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc

eleration of the crate after it begins to move
Physics
1 answer:
Nookie1986 [14]2 years ago
8 0

The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

Mass (m) = 50 Kg

Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

<h3>Fբ = 75 N</h3>

  • Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

<h3>Net force (Fₙ) =?</h3>

Fₙ = F – Fբ

Fₙ = 100 – 75

<h3>Fₙ = 25 N</h3>

  • Finally, we shall determine the acceleration of the crate

Mass (m) = 50 Kg

Net force (Fₙ) = 25 N

<h3>Acceleration (a) =?</h3>

a = Fₙ / m

a = 25 / 50

<h3>a = 0.5 m/s²</h3>

Therefore, the acceleration of the crate is 0.5 m/s²

Learn more on friction: brainly.com/question/364384

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eimsori [14]
The time described above is known as the waves Period.
The time which it takes for a particle to complete one full cycle is known as the period. Period is normally measured in seconds. Frequency on the other hand is the number of cycles which are completed in a given period of time e.g a second. periodic time T is given by reciprocal of frequency (1/f).
6 0
3 years ago
A commuter train travels from New York to Washington, DC, and back in 6 hours and 5 minutes. The distance between the two statio
vovikov84 [41]

Answer:

The train's displacement is zero.

Explanation:

Given data,

The time taken by the train from NY to Washington and back is, t = 6 h 5 min

The distance between the two stations is, d = 363 km

Therefore, the total distance the train traveled is, d' = 726 km

The displacement is defined as the change in position coordinates with respect to its original position.

If the train travels from one point and returns back to the same point after some time, there is no change in the position coordinates with respect to its original position.

Hence, the train's displacement is zero.

3 0
4 years ago
A food department is kept at â12°c by a refrigerator in an environment at 30°c. the total heat gain to the food department is
slava [35]

As per energy conservation in the reversible engine we can say

Q_2 + W = Q_1

here we know that

Q_2 = 3300 kJ/h

Q_1 = 4800 kJ/h

now from above equation

3300 + W = 4800

W = 1500 kJ/h

now we can convert it into kW

W = 1500\times \frac{kJ}{3600s}

W = 0.42 kW

so above is the power input to the refrigerator

now to find COP we know that

COP = \frac{Q_2}{W}

COP = \frac{3300}{1500} = 2.2

so COP of refrigerator is 2.2

3 0
3 years ago
A sprinter generates a constant force of 52 N as he runs 100 m. How much work did he do?
LUCKY_DIMON [66]
You just multiply these two numbers. It's 5200J, or 5.2kJ
3 0
3 years ago
A force of 40 N is required to hold a spring that has been stretched from its natural length of 10 cm to a length of 15 cm. How
Sati [7]

0.36 J of work is done in stretching the spring from 15 cm to 18 cm.

To find the correct answer, we need to know about the work done to strech a string.

<h3>What is the work required to strech a string?</h3>
  • Mathematically, the work done to strech a string is given as 1/2 ×K×x².
  • K is the spring constant.
<h3>What will be the spring constant, if 40N force is required to hold a 10 cm to 15 cm streched spring?</h3>
  • The force experienced by a streched spring is given as Kx. x is the length of the spring streched from its natural length.
  • Then K = Force / x.
  • Here x = 15 - 10 = 5 cm = 0.05 m
  • K = 40/0.05 = 800N/m.
<h3>What will be the work required to strech that spring from 15 cm to 18 cm?</h3>
  • Work done = 1/2×k×x²
  • Here x= 18-15=3cm or 0.03 m
  • So, W= 1/2×800×0.03² = 0.36 J.

Thus, we can conclude that the work done is 0.36 J.

Learn more about the spring force here:

brainly.com/question/14970750

#SPJ4

6 0
2 years ago
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