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4 years ago

What was one result of the second great awakening

Physics

1 answer:

Brrunno [24]4 years ago

4 0

The membership rose among the baptist and methodists.

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True or False: If your gas pedal jams, you should turn the key to lock to lock the steering wheel.

Bond [772]

Answer:False

Explanation:

Turn the key to lock is not advisable as it lock the steering wheel and may create a dangerous situation.

Following steps can be taken in this situation

Try to press the brake to stop the vehicle
Shift gear to neutral in order to cease the acceleration of car.
Try to lift the gas pedal in order to decrease the velocity of car.

5 0

3 years ago

Read 2 more answers

Using the definition of moment of inertia, calculate icm, the moment of inertia about the center of mass, for this object.

Step2247 [10]

<span> The masses have no inertia about their own CM, and "the object" is the two masses. </span>
<span>1. Icm (at point A) = 2mr^2
hope this helps</span>

3 0

3 years ago

Two oppositely charged parallel sheets of charge give rise to a field of 9.00×1011 N/C between them. The sheets are square and h

Maksim231197 [3]

Answer:

$Q = 5.75 C$

Explanation:

As we know that due to a thin sheet electric field at a point near its surface is given as

$E = \frac{\sigma}{2\epsilon_0}$

now we have two sheets of opposite charges so the net electric field is double that of field due to one sheet

so we have

$E_{net} = 2E$

$E_{net} = \frac{\sigma}{\epsilon_0}$

$9.00 \times 10^{11} = \frac{Q}{A\epsilon_0}$

now we have

$Q = 9.00 \times 10^{11}(0.85 \times 0.85)(8.85 \times 10^{-12})$

$Q = 5.75 C$

8 0

4 years ago

A 10.0-kg box starts at rest on a level floor. An external, horizontal force of 2.00 × 102 N is applied to the box for a distanc

Harman [31]

Answer:

vf = 11.2 m/s

Explanation:

m = 10 Kg

F = 2*10² N

x = 4.00 m

μ = 0.44

vi = 0 m/s

vf = ?

We can apply Newton's 2nd Law

∑ Fx = m*a (→)

F - Ffriction = m*a ⇒ F - (μ*N) = F - (μ*m*g) = m*a ⇒ a = (F - μ*m*g)/m

⇒ a = (2*10² N - 0.44*10 Kg*9.81 m/s²)/10 Kg = 15.6836 m/s²

then , we use the equation

vf² = vi² + 2*a*x ⇒ vf = √(vi² + 2*a*x)

⇒ vf = √((0)² + 2*(15.6836 m/s²)*(4.00m)) = 11.2 m/s

7 0

3 years ago

Calculate the diffraction limit of the human eye, assuming a wide-open pupil so that your eye acts like a lens with diameter 0.8

guapka [62]

Hi, thank you for posting your question here at Brainly.

This problem could be solved using this equation:

Diffraction limit = 1.22*wavelength/diameter

diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m

Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625

6 0

3 years ago