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1 year ago

(01.05 LC)

Chemistry

2 answers:

wel1 year ago

7 0

Answer:

it is A trust me I know thank you

Svetradugi [14.3K]1 year ago

7 0

A solid dissolves in liquid because that makes most sense to me

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Calculate the equilibrium constant for the reaction: 2 Cr + 3 Pb2+ ----> 3 Pb + 2 Cr3+ at 25oC. Eocell = 0.61 V

sattari [20]

Answer:

The value is $K = 8*10^{61}$

Explanation:

From the question we are told that

The equation is $2 Cr + 3Pb^{2+} \to 3Pb + 2Cr^{3+}$

The temperature is $T = 25^oC = 298 K [room \ temperature ]$

The emf at standard condition is $E^o_{cell} = 0.61 \ V$

Generally at the cathode

$3Pb^{2+}(aq) + 6 e- --> 3Pb(s)$

At the anode

$2Cr^{3+} + 6e^- \to 2Cr$

Generally for an electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as

$G = n* F * E^o_{cell}$

Here n is the no of electron with value n = 6

F is the Faraday's constant with value 96487 J/V

=> $G = 6 * 96487 * 0.61$

=> $G = 3.5 *10^{5} \ J$

This Gibbs free energy can also be represented mathematically as

$G = RTlogK$

Here R is the cell constant with value 8.314J/K

K is the equilibrium constant

From above

=> $K = antilog^{\frac{G}{ RT} }$

Generally antilog = 2.718

=> $K = 2.718^{\frac{3.5 *10^5}{ 8.314* 298} }$

=> $K = 8*10^{61}$

6 0

2 years ago

Which reaction type is the following: AgF + CaCl2 --> AgCl + CaF2

nevsk [136]

Explanation:

${\small{\underline{\bf{\red{answer...}}}}} \\ \\$

$\small\mathfrak\purple{Double \: displacement \: reaction} \\ \\ \small\mathfrak\orange{hope \: it \: helps...}$

6 0

2 years ago

I am having some trouble figuring out how to approach the following problem: A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is ti

Tanya [424]

<span>We look at the end of the day:

n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
pOH = -log[OH-] ≈ 5.8956 pH = 14 - pOH ≈ 8.10</span>

4 0

2 years ago

What is the molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bonds?

liq [111]

The molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bond is C₁₄H₂₀

<h3>Molecular formula</h3>

A formula that gives the number of atom of each element present in a one molecule or a compound.

<h3>Monocyclic hydrocarbons</h3>

The name of the saturated hydrocarbons formed by the name attaching the perfix cyclo to the name of acyclic unstaturated hydrocarbon

The molecular formula for a monocyclic hydrocarbon with 14 carbon and 2 triple bonds is C₁₄H₂₀

Learn more about the molecular formula on

brainly.com/question/11558543