Option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.
<h3>
Reaction between oxygen and ethene</h3>
Ethene (C2H4) burns in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O) along with the evolution of heat and light.
C₂H₄ + 3O₂ ----- > 2CO₂ + 2H₂O
from the equation above;
3 moles of O₂ ---------> 2(18 g) of water
3.5 moles of O₂ ----------> x
![x = 3.2 \times [\frac{2 \ moles \ H_2O}{3 \ moles \ O_2} ] \times[ \frac{18.02 \ g \ H_2O}{1 \ mole \ H_2O} ]](https://tex.z-dn.net/?f=x%20%3D%203.2%20%5Ctimes%20%5B%5Cfrac%7B2%20%5C%20moles%20%5C%20H_2O%7D%7B3%20%5C%20moles%20%5C%20O_2%7D%20%20%5D%20%5Ctimes%5B%20%5Cfrac%7B18.02%20%5C%20g%20%5C%20H_2O%7D%7B1%20%5C%20mole%20%5C%20H_2O%7D%20%5D)
Thus, option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.
Learn more about reaction of ethene here: brainly.com/question/4282233
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The atomic number is the number of Protons on the nucleus of the atom, whereas the mass number of some isotope is the mass of the protons plus the mass of the neutrons. That's the difference between isotopes: number of neutrons.
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pH = -log[H₃O⁺(aq)]
here the pH is given as 2.40.
Hence,
2.40 = -log[H₃O⁺(aq)]
log[H₃O⁺(aq)] = -2.40
[H₃O⁺(aq)] = 3.98 x 10⁻³ M
= 4.0 x 10⁻³ M
Hence, the hydronium ion concentration in juice is 4.0 x 10⁻³ M.
Since, the pH is less than 7, the juice is acidic.
1.05 x 10 to the 21 power formula units of lead (IV) phosphate
Explanation:
A metal atom loses electrons and becomes a positive ion.
