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3 years ago

Someone please help!!!!! i will mark brainliest :)

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

7 0

Answer:

you have to solve all of the equations i none square and then once you have all of the answers in each square, add them up and then solve the questions down below

Step-by-step explanation:

correct me if im wrong

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Answer please thanks

Naddik [55]

Answer:

-37/6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please help with scale factor!!!!!!!! I will mark brainliest if right! Two rectangular prisms have a side scale factor of 1/4. I

Agata [3.3K]

Answer:

1/16
720 cm²

Step-by-step explanation:

Area is the product of two dimensions.

If the scale factor is 1/4, the ratio of the areas will be:

(1/4)² = 1/16

The smaller prism has a surface are of 45 cm².

The larger prism has a surface area:

45*16 = 720 cm²

5 0

2 years ago

Paul's family drove 377 mi to the beach averaging 58 mi/h on the way there. On the return trip home, they averaged 65 mi/h

sashaice [31]

The answer is 12.3 hours

6 0

3 years ago

PLEASE HELP 100!!! POINTS

faust18 [17]

Answer:

Most Unlikely: Less than 5

Likely: 2-digit number

Unlikely: Multiple of 3

Equally Likely: Odd

Most Likely: Greater than 10

Step-by-step explanation:

there are 6x5, or 30 outcomes

Less than 5 has 1 outcome - spinner and dice both are one

Odd has 15 outcomes

Multiple of 3 has 8 outcomes: 1+5, 2+1, 2+7, 2+12, 3+12, 4+5, 5+7, 5+10

Two-digits has 12 outcomes

Greater than ten has 16 outcomes

6 0

2 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

2 years ago