A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions

Question

nasty-shy [4]

2 years ago

12

A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions

effuses in 2. 42 minutes. what is the molar mass of the unknown gas?

Chemistry

1 answer:

Damm [24] · Answer 1 · 2023-10-07T21:52:39+03:00

A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions effuses in 2. 42 minutes then the molar mass of the unknown gas is 41.9.

Molar mass of H2 = 2

Molar mass of unknown gas = ?

rate 1 = 11.1

rate 2 = 2.42

<h3>What is graham law? </h3>

Graham's law states that the rate of diffusion or effusion of a given gas is inversely proportional to the square root of its molar mass.

By apply graham law

Rate1/rate2 = sqrt(MW2/MW1)

$[\frac{rate1}{rate2} ]^{2} = \frac{MW2}{2} \\\\\\mw= 2[\frac{11.1}{2.42} ]^{2} \\\\= 20.97 X 2 \\\\= 41.9$

Thus, we found that the molar mass of the unknown gas is 41.9.

Learn more about graham's law: brainly.com/question/12415336

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