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AveGali [126]
2 years ago
15

How long is a bench? Select the best estimate.

Chemistry
1 answer:
Alenkinab [10]2 years ago
8 0

Answer:

4 meters

Explanation:

4 centimeters and millimeters are too small, while 4 kilometers is too large.

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The distances from large bodies of water will affect the average rainfall of an area. (Example: Florida has more rain than Nevad
lions [1.4K]

Answer:

A

Explanation:

7 0
3 years ago
What did J. J. Thomson observe when he applied electric voltage to a cathode ray tube in his famous experiment?
Nataly_w [17]

The glass opposite to the negative electrode started to glow. Hence, option B is correct.

<h3>What is a cathode ray tube?</h3>

A cathode-ray tube (CRT) is a specialized vacuum tube in which images are produced when an electron beam strikes a phosphorescent surface.

J.J. Thomson, through his famous Cathode ray experiment, proved that all atoms contain small negatively charged particles known as electrons. In the experiment, he applied electric voltage across a cathode ray tube. a fluorescent material coating was done on the positive side. When the voltage was applied, the positive side has glowing dots.

Hence, option B is correct.

Learn more about the cathode ray tube here:

brainly.com/question/14409449

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6 0
2 years ago
Prokaryotic is an example of a/an-<br><br> A:tissue <br> B:cell type<br> C:organ<br> D:organism
Leto [7]

Answer:

B. Cell Type

Explanation:

that is the answer i believe

6 0
3 years ago
Read 2 more answers
Why might nuclear fusion be a better source of energy on earth than nuclear fission?
AleksAgata [21]
<span>Cost and availability of fuel is a considerable factor when dealing with nuclear power. Fission requires an element that can be easily split in a particle accelerator, such as uranium or plutonium. Fusion, on the other hand, uses isotopes of hydrogen atoms, specifically deuterium and tritium, that can be obtained from ordinary water</span>
5 0
4 years ago
What is the pH of 0.10 M NaF(aq). The Ka of HF is 6.8 x 10-4
dsp73

<u>Given information:</u>

Concentration of NaF = 0.10 M

Ka of HF = 6.8*10⁻⁴

<u>To determine:</u>

pH of 0.1 M NaF

<u>Explanation:</u>

NaF (aq) ↔ Na+ (aq) + F-(aq)

[Na+] = [F-] = 0.10 M

F- will then react with water in the solution as follows:

F- + H2O ↔ HF + OH-

Kb = [OH-][HF]/[F-]

Kw/Ka = [OH-][HF]/[F-]

At equilibrium: [OH-]=[HF] = x and [F-] = 0.1 - x

10⁻¹⁴/6.8*10⁻⁴ = x²/0.1-x

x = [OH-] = 1.21*10⁻⁶ M

pOH = -log[OH-] = -log[1.21*10⁻⁶] = 5.92

pH = 14 - pOH = 14-5.92 = 8.08

Ans: (b)

pH of 0.10 M NaF is 8.08

6 0
3 years ago
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