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Zepler [3.9K]
3 years ago
14

A box of paper clips weighs 1.1 kg. If each paper clip weighs 0.88 grams, how many paper clips are in the box? (Hint: 1 kg = 100

0 grams).
Chemistry
2 answers:
Kisachek [45]3 years ago
6 0
Answer:

there are exactly 1,250 paper clips in that box.

goodluck!!

support me by marking as brainliest!! :)
PolarNik [594]3 years ago
5 0
1.1kg = 1100g
If each paper clip is 0.88g : 1100 / 0.88 = 1250
1250 paper clips in the box
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A flask contains 0.83molof neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the
blsea [12.9K]

Answer:

V = 56.72 L

Explanation:

Given data:

Number of mole of neon gas = 0.83 mol

Temperature = 35°C

Pressure = 0.37 atm

Volume of gas = ?

Solution;

Temperature = 35°C  (35+273 =308K)

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

Now we will put the values in formula.

V = nRT/P

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6 0
3 years ago
Which of these, if dissolved in 1.0 l of pure water, would produce a buffer solution? which of these, if dissolved in 1.0 l of p
stiks02 [169]

Answer:

  1. (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄)

Explanation:

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid.

Also, a buffer solution is a solution which resists changes in pH when acid or alkali is added to it.

  1. (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄) when dissolved in 1 L H₂O will produce a buffer because NaH₂PO₄ is considered as weak acid while Na₂HPO₄ is its conjugate base. 2.
  2. (0.1 mol H₃O⁺ + 0.1 mol Cl⁻) is not a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid.
  3. (0.1 mol HCl + 0.1 mol NaoH) HCL is a strong acid and NaOH is a strong base so it will not form a buffer when dissolved in water.
  4. (0.1 mol H₃O⁺ + 0.1 OH⁻) is not a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid
  5. (0.1 mol NaCl+ 0.1 mol KCl) NaCL and KCL are salts so it will not form a buffer when dissolved in water.

So the right choice is

  1. (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄)

7 0
3 years ago
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