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Alja [10]
3 years ago
5

Magnesium metal burning in oxygen gas t

Chemistry
1 answer:
Gelneren [198K]3 years ago
3 0

Answer:

aluminium iodide

Explanation:

Al+ I2=AlI

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In a solution of pure water, the dissociation of water can be expressed by the following: H2O(l) + H2O(l) ⇌ H3O+(aq) + OH−(aq) T
kakasveta [241]

Answer:

  • [H₃O⁺] = 2.90 × 10⁻¹⁰ M

Explanation:

1)<u><em> Ionization equilibrium equation: given</em></u>

  • H₂O(l) + H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq)

2) <em><u>Ionization equilibrium constant, at 25°C, Kw: given</u></em>

  • Kw = 1.0 × 10⁻¹⁴

<u>3) Stoichiometric mole ratio:</u>

As from the ionization equilibrium equation, as from the fact it is stated, the concentration of both ions, at 25°C, are equal:

  • [H₃O⁺(aq)] = [OH⁻(aq)] = 1.0 × 10⁻⁷ M

  • ⇒ Kw = [H3O⁺] [OH⁻] = 1.0 × 10⁻⁷  × 1.0 × 10⁻⁷  = 1.0 × 10⁻¹⁴ M

<u><em>4) A solution has a [OH⁻] = 3.4 × 10⁻⁵ M at 25 °C </em></u><em><u>and you need to calculate what the [H₃O⁺(aq)] is.</u></em>

Since the temperature is 25°, yet the value of Kw is the same, andy you can use these conditions:

  • Kw = 1.0 × 10⁻¹⁴ M², and

  • Kw = [H3O⁺] [OH⁻]

Then you can substitute the known values and solve for the unknown:

  • 1.0 × 10⁻¹⁴ M² = [H₃O⁺] × 3.4 × 10⁻⁵ M

  • ⇒ [H₃O⁺]  = 1.0 × 10⁻¹⁴ M² / ( 3.4 × 10⁻⁵ M ) = 2.9⁻¹⁰ M

As you see, the increase in the molar concentration of the ion [OH⁻] has caused the decrease in the molar concentration of the ion [H₃O⁺], to keep the equilibrium law valid.

6 0
3 years ago
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Cual es el volumen de la solución de hcl la cual se preparo con 3 gramos de soluto (k) al 14%
Elena-2011 [213]

Answer:

from which language this belongs to

3 0
3 years ago
This element has 80 electrons and is considered a transitional element. What am I?
sdas [7]

Answer:its mercury i think!!!!!

Explanation:

8 0
2 years ago
Which is a FALSE statement about the possible benefits of nanocars? A. They could work together to build really complex things.
kondor19780726 [428]
C, they could work together to make things from the top down. 
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3 years ago
You decide to establish a new temperature scale on which the melting point of ammonia (-77.75 ∘c) is 0∘a, and the boiling point
Hoochie [10]
First we need to know that the boiling point of water in C is 100 and we just need to solve for x in the equation:

-33.75-(-77.75) / 100 = 100-(-77.75) / x
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The boiling point of water in ∘a would be 400.33∘a.

7 0
3 years ago
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