Answer:Find the distance between the parallel lines m and n whose equations are y = x + 4 and y = x - 6, respectively.
There are several ways to do this...here's one
Let (0, 4) be a point on the first line
Then.......a line with a negative reciprocal slope going through this point will have the equation :
y = -x + 4........so......we can find the intersection of this line with y = x - 6....set both equations equal
-x + 4 = x - 6 add x, 6 to both sides
10 = 2x divide both sides by 2
5 = x
So...using -x + 4, the y value at intersection = -1.......
So...we just need to find the distance from (0,4) to ( 5, -1) =
√[ (5)^2 + (4 + 1)^2 ] = 5√2 ≈ 7.07 units
Here's a pic....AB is the distance with A = (0,4) and B = (5, -1)
Step-by-step explanation:
Answer:
m =3/4
Step-by-step explanation:
3x-4y = 12
We need to solve for y
Subtract 3x from each side
3x-3x-4y = -3x+12
-4y = -3x+12
Divide by -4
-4y/-4 = -3x/-4 + 12/-4
y = 3/4 x -3
This is in the form y = mx+b where m is the slope and b is the y intercept
The slope is 3/4
Answer:
Step-by-step explanation:
Use the point-slope formula.
y - y_1 = m(x - x_1) you have : x_1 =5 and y_1 =1
m the slope m= -1 (same slope for the line : x+y=9 because this lines are parallel and you can write y=-x+9
an equation for this line is : y-1 = -(x-5)
1.9
Do sin54 * 2.3
Because sin54 = x/2.3
Answer:
6+x or x+6
Step-by-step explanation:
Hey.
6 more than x can be written as
6 + x
<em>Hope I helped, Feel free to ask any questions to clarify.</em>
<em> -Aadi x</em>
