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Nostrana [21]
3 years ago
15

The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe

cimens is collected. What is the standard error of the sample mean?
Round your final answer to three decimal places (e.g. 12.345).

The standard error of the sample mean is __ psi.
Mathematics
1 answer:
ipn [44]3 years ago
7 0

Answer:

The standard error of the sample mean is _17.677_ psi.

Step-by-step explanation:

<u>Explanation</u>:-

A random sample of n = 8 specimens is collected.

Given sample size is n = 8

Given mean of the population 'μ' = 2500 psi

standard deviation 'σ' = 50 psi

Let x⁻ is the mean of the observed sample

Standard error of the sample mean = \frac{S.D}{\sqrt{n} }      ...(i)

Given Population of standard error (S.D) 'σ' = 50 psi

Now substitute all values in (i)

S.E = \frac{50}{\sqrt{8} } =17.677

<u>Conclusion</u>:-

The standard error of the sample mean is _17.677psi.

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Solve the system by substitution<br> -4.5x-2y=-12.5<br> 3.25x-y=-0.75
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Answer:

The answer to your question is: x = 1, y = 4

Step-by-step explanation:

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4.5 = 9/2

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                             -9/2 x - 2 y = - 25/2         (I)

                             13/4 x  -   y  = - 3/4            (ll)

Process

               from (II)     y = 13/4x  + 3/4

Sunstitution             -9/2x -2(13/4 x + 3/4) = - 25/2

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                             y = 16/4

                             y = 4                                          

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