Answer: It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
Step-by-step explanation:
Let us consider the general linear equation
Y = MX + C
On a coordinate plane, a line goes through points (0, negative 1) and (2, 0).
Slope = ( 0 - -1)/( 2- 0) = 1/2
When x = 0, Y = -1
Substitutes both into general linear equation
-1 = 1/2(0) + C
C = -1
The equations for the coordinate is therefore
Y = 1/2X - 1
Let's check the equations one after the other
y = negative one-half x minus 1
Y = -1/2X - 1
y = negative one-half x + 1
Y = -1/2X + 1
y = one-half x minus 1
Y = 1/2X - 1
y = one-half x + 1
Y = 1/2X + 1
It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
1. -1, 2,8,11
plug the values into the equation and solve
Ur answer is going to be 78.507
Well an axis is like the whole line, so I would think its A, hope this helps.
Based on the calculations, the coordinates of the mid-point of BC are (1, 4).
<h3>How to determine coordinates of the mid-point of BC?</h3>
First of all, we would determine the initial y-coordinate by substituting the value of x into the equation of line that is given:
At the origin x₁ = 0, we have:
y = 2x + 1
y₁ = 2(0) + 1
y₁ = 2 + 1
y₁ = 3.
When x₂ = 2, we have:
y = 2x + 1
y₂ = 2(2) + 1
y₂ = 4 + 1
y₂ = 5.
In order to determine the midpoint of a line segment with two (2) coordinates or endpoints, we would add each point together and divide by two (2).
Midpoint on x-coordinate is given by:
Midpoint = (x₁ + x₂)/2
Midpoint = (0 + 2)/2
Midpoint = 2/2
Midpoint = 1.
Midpoint on y-coordinate is given by:
Midpoint = (y₁ + y₂)/2
Midpoint = (3 + 5)/2
Midpoint = 8/2
Midpoint = 4.
Therefore, the coordinates of the mid-point of BC are (1, 4).
Read more on midpoint here: brainly.com/question/4078053
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