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inessss [21]
3 years ago
9

Drag each item to the container that best describes it.

Engineering
2 answers:
LenKa [72]3 years ago
7 0

Answer:

If this is what I think it is...

Explanation:

Rate: 1 sheet per 4 paragraphs, 1 page for every four students

Unit Rate: 500 sheets per ream, 40 pages for each booklet, 15 pages for each booklet

Neither: 25 pages

Step-by-step explanation:

To do this you just need to remember the difference between Unit Rate and Rate, the Unit rate make reference to those rates in which the numerator is one, so you saying there are 3 candies for each kid, that is a unit rate, saying there is one kid for every three candies that is a rate, so that´s how you divide them, that´s why even though 1 sheet per 4 paragraphs, 1 page for every four students have one in their fractions, they are rates and not unit rates because the one is not in the numerator.

boyakko [2]3 years ago
7 0

Answer:

Rate: 1 sheet per 4 paragraphs, 1 page for every four students

Unit Rate: 500 sheets per ream, 40 pages for each booklet, 15 pages for each booklet

Neither: 25 pages

Step-by-step explanation:

To do this you just need to remember the difference between Unit Rate and Rate, the Unit rate make reference to those rates in which the numerator is one, so you saying there are 3 candies for each kid, that is a unit rate, saying there is one kid for every three candies that is a rate, so that´s how you divide them, that´s why even though 1 sheet per 4 paragraphs, 1 page for every four students have one in their fractions, they are rates and not unit rates because the one is not in the numerator.

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Of course they are needed because without them the society wouldn’t be as nice as it is right now and plus there would be no more buildings ! :)
8 0
3 years ago
You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea
Reika [66]

Answer: 33.35 minutes

Explanation:

A(t) = A(o) *(.5)^[t/(t1/2)]....equ1

Where

A(t) = geiger count after time t = 100

A(o) = initial geiger count = 400

(t1/2) = the half life of decay

t = time between geiger count = 66.7 minutes

Sub into equ 1

100=400(.5)^[66.7/(t1/2)

Equ becomes

.25= (.5)^[66.7/(t1/2)]

Take log of both sides

Log 0.25 = [66.7/(t1/2)] * log 0.5

66.7/(t1/2) = 2

(t1/2) = (66.7/2 ) = 33.35 minutes

4 0
3 years ago
For installations where the nonlinear load is huge, most consulting engineers will specify ____-rated transformers.
Scorpion4ik [409]

Answer:

K

Explanation:

For installations where the nonlinear load is huge, most consulting engineers will specify K-rated transformers.

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