How do I do science it just don’t show a true display of skill

Are currently supporting communities affected by GBV in community violations

White raven [17]

Answer:By obey peoples propertice

Explanation:

8 0

2 years ago

A vacuum gage connected to a chamber reads 35 kPa at a location where the atmospheric pressure is 92 kPa. The absolute pressure

Elodia [21]

Answer:

Absolute pressure= 57 KPa

Explanation:

Given that

Vacuum gauge pressure = 35 KPa

Atmospheric pressure = 92 KPa

We know that

Absolute pressure=Atmospheric pressure + gauge pressure

But we should remember that Vacuum gauge pressure is also called negative gauge pressure.So when given that pressure is vacuum gauge then subtract gauge pressure from atmospheric pressure instead of addition.

So now by putting the values

Absolute pressure=Atmospheric pressure - Vacuum gauge pressure

Absolute pressure=92 - 35 KPa

Absolute pressure= 57 KPa

7 0

3 years ago

ear shaft.3. Chapter 12 –Loading on Spur Gears: A 26-tooth pinion rotating at a uniform 1800 rpm meshes with a 55-tooth gear in

Mama L [17]

Answer:

The bending stress is 502.22 MPa

Explanation:

The diameter of the pinion is equal to:

$d_{p} =mN_{p}$

Where

m = module = 5

Np = number of teeth of pinion = 26

$d_{p} =5*26=130mm$ = 0.13 m

The pitch line velocity is equal to:

$V_{t} =\frac{d_{p}*2*\pi *w_{p} }{120}$

Where

wp = speed of the pinion = 1800 rpm

$V_{t} =\frac{0.13*2*\pi *1800}{120} =12.25m/s$

The factor B is equal to:

$B=\frac{(12-Q_{v})^{2/3} }{4} , if Q_{v} =10\\B=\frac{(12-10)^{2/3} }{4} =0.396$

The factor A is equal to:

A = 50 + 56*(1 - B) = 50 + 56*(1-0.396) = 83.82

The dynamic factor is:

$K_{v} =(\frac{A}{A+\sqrt{200V_{t} } } )^{B} \\K_{v}=(\frac{83.82}{83.82+\sqrt{200*12.25} } )^{0.396} =0.832$

The geometry bending factor at 20°, the application factor Ka, load distribution factor Km, the size factor Ks, the rim thickness factor Kb and Ki the idler factor can be obtained from tables

JR = 0.41

Ka = 1

Kb = 1

Ks = 1

Ki = 1.42

Km = 1.7

The diametrical pitch is equal to:

$P_{d} =\frac{1}{m} =\frac{1}{5} =0.2mm^{-1}$

The bending stress is equal to:

$\sigma =\frac{W_{t}P_{d}K_{a}K_{m}K_{s}K_{b}K_{i} }{FJ_{g}K_{v}} \\\sigma =\frac{22000*0.2*1*1.7*1*1*1.42}{62*0.41*0.832} =502.22MPa$

4 0

3 years ago

Is a gas turbine a heat engine?

Nookie1986 [14]

Gas turbines extract the energy from combustion gas

and heat engines convert thermal and chemical energy to mechanical energy

gas is considered a chemical so i'm pretty sure it is considered one

4 0

3 years ago

Write a SELECT statement that returns the same result set as this SELECT statement, but don’t use a join. Instead, use a subquer

Bess [88]

Answer:

See explanation

Explanation:

The complete question is

Write a SELECT statement that returns the same result set as this SELECT statement, but don't use a

join. Instead, use a subquery in a WHERE clause that uses the IN keyword.

SELECT DISTINCT category_name

FROM categories c JOIN products p

ON c.category_id = p.category_id

ORDER BY category_name

The join clause gives us all the registers of both tables, for which the category_id of categories coincides to the category_id in the table products. That is, we can first select the distinct category_id's from products and the see the categories from categories table, whose id is in that list. That means writing the following query:

Select distinct category_name

from categories c

where c.category_id in (

select distinct p.category_id

from products p)

order by category_name

4 0

4 years ago