Answer:
I)E= 40.95 GPa
II)E=5.29 GPa
Explanation:
I)
Given that
E₁ = 2.41 GPa ,V₁=1-0.55 = 0.45
E₂ = 72.5 GPa ,V₂=0.55
Longitudinal moduli given as ;
E= E₁V₁+E₂V₂
E= 2.41 x 0.45 + 72.5 x 0.55 GPa
E= 40.95 GPa
II)
E₁ = 2.41 GPa ,V₁=1-0.55 = 0.45
E₂ =230 GPa ,V₂=0.55
Transverse moduli given as:
E=5.29 GPa
Question:
All of the following are advantages of using a pressure transducer rather than a vacuum gauge EXCEPT:
A. greater accuracy.
B. easier identification of the cylinder.
C. measuring higher pressures.
D. ability to see the levels graphically
Answer:
The correct answer is D) ability to see the levels graphically
Explanation:
The above question derives from the Rudiments of Automotive Technology.
The function of the pressure transducer is to enable the diagnostic who is testing the engine vacuum to detect the cylinder with a faulty vacuum.
The pressure transducer does allow its user to see the vacuum graphically NOT the levels.
Cheers.
Answer:
Hf = 0.0204 Ft.
Explanation:
See attachment for detailed answer.
I because u cannot specify hmm good question