Safety measures to be taken during technical drawing<br>

To do a research, a researcher needs to be clear about what he/she is doing, why he/she is doing it and the associated implicati

Mashutka [201]

Answer:

True

Explanation:

To carry out a research in order to that it should yield the desirable result, a researcher must be very clear about his objective for the research.

The researcher must be very much clear about all the do's and don'ts and all the where, why, what sort of thing, i.e., the researcher must be clear about his/her intentions of carrying out the research, and what research is being carried out by him/her.

The one doing the research must be clear about the implications of the research.

Unless all these things are not clear at the researcher's end the research will not give the desired results.

4 0

3 years ago

Oil with a density of 850 kg/m3 and kinematic viscosity of 0.00062 m2 /s is being discharged by a 5 mm diameter, 40 m long horiz

ra1l [238]

Answer:

Flow rate is $1.82\times 10^{-8} m^{3}/s$

Explanation:

Given information

Density of oil, $\rho_{oil}= 850 Kg/m^{3}$

kinematic viscosity, $v= 0.00062 m^{2} /s$

Diameter of pipe, D= 5 mm= 0.005 m

Length of pipe, L=40 m

Height of liquid, h= 3 m

Volume flow rate for horizontal pipe will be given by

$\bar v=\frac {\triangle P\pi D^{4}}{128\mu L}$ where $\mu$ is dynamic viscosity and $\triangle P$ is pressure drop

At the bottom of the tank, pressure is given by

$P_{bottom}=\rho_{oil} gh=850 Kg/m^{3}\times 9.81 m/s^{2}\times 3 m= 25015.5 N/m^{2}$

Since at the top pressure is zero, therefore change in pressure a difference between the pressure at the bottom and the top. It implies that change in pressure is still $25015.5 N/m^{2}$

Dynamic viscosity, $\mu=\rho_{oil}v= 850 Kg/m^{3}\times 0.00062 m^{2}/s=0.527 Kg/m.s$

Now the volume flow rate will be

$\bar v=\frac {25015.5 N/m^{2}\times \pi \times 0.005^{4}}{128\times 0.527 Kg/m.s \times 40}=1.82037\times 10^{-8} m^{3}/s\approx 1.82\times 10^{-8} m^{3}/s$

Proof of flow being laminar

The velocity of flow is given by

$V_{flow}=\frac {\bar v}{A}=\frac {1.82\times 10^{-8} m^{3}/s}{0.25\times \pi\times 0.005^{2}}=0.000927104 m/s$

Reynolds number, $Re=\frac {\rho_{oil} v_{flow} D}{\mu}=\frac {850 Kg/m^{3}\times 0.000927104 m/s\times 0.005}{0.527 kg/m.s}=0.007476648$

Since the Reynolds number is less than 2300, the flow is laminar and the assumption is correct.

5 0

4 years ago

“Convection is equal to the Conduction plus <br><br>fluid flow.”

zysi [14]

Answer:

Conduction is the transfer of heat by contact, mostly in solids (metals especially) . In conduction, the molecules of the body in contact with the hot body vibrates about a fixed point. The vibration causes collision between these vibrating molecules and their neighboring molecule, causing them to vibrate too; creating a wave of vibrating molecules that transfer the heat along the solid material.

Convection is the transfer of heat in fluids (liquids and gases), that involves the initial heat transfer between a portion of the fluids molecules and the hot body (conduction) at the thermal boundary, and then the eventual movement of that portion of the fluid from that position to a colder part of the fluid. The heated fluid is replaced by a colder fluid (this is due to buoyant forces due to difference in density of the cold and the warm parts of the fluid). This movement ensure thorough mixing of the fluid and the eventual heating up of the entire fluid.

From the above statements one can clearly see that convection is comprised of an initial heat transfer by conduction at the thermal boundary, followed by movement of the fluid molecules.

8 0

3 years ago

During normal operation, an electrical component experiences a constant rate of ohmic dissipation ini g = 0.01 W that causes the

Llana [10]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to your answer.