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algol13
3 years ago
7

How to calculate maximum shear stress in the cross-section of a beam if the neutral axis is not on the thinnest part of the cros

s-section?
Engineering
1 answer:
likoan [24]3 years ago
5 0

—By the maximum shear stress is then calculated by: where b = 2 (ro − ri) is the effective width of the cross section, Ic = π (ro4 − ri4) / 4 is the centroidal moment of inertia, and A = π (ro2 − ri2) is the area of the cross section.

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You are evaluating the lifetime of a turbine blade. The blade is 4 cm long and there is a gap of 0.16 cm between the tip of the
Tcecarenko [31]

Answer:

Explanation:

Given conditions

1)The stress on the blade is 100 MPa

2)The yield strength of the blade is 175 MPa

3)The Young’s modulus for the blade is 50 GPa

4)The strain contributed by the primary creep regime (not including the initial elastic strain) was 0.25 % or 0.0025 strain, and this strain was realized in the first 4 hours.

5)The temperature of the blade is 800°C.

6)The formula for the creep rate in the steady-state regime is dε /dt = 1 x 10-5 σ4 exp (-2 eV/kT)

where: dε /dt is in cm/cm-hr σ is in MPa T is in Kelvink = 8.62 x 10-5 eV/K

Young Modulus, E = Stress, \sigma /Strain, ∈

initial Strain, \epsilon_i = \frac{\sigma}{E}

\epsilon_i = \frac{100\times 10^{6} Pa}{50\times 10^{9} Pa}

\epsilon_i = 0.002

creep rate in the steady state

\frac{\delta \epsilon}{\delta t} = (1 \times {10}^{-5})\sigma^4 exp^(\frac{-2eV}{kT} )

\frac{\epsilon_{initial} - \epsilon _{primary}}{t_{initial}-t_{final}} = 1 \times 10^{-5}(100)^{4}exp(\frac{-2eV}{8.62\times10^{-5}(\frac{eV}{K} )(800+273)K} )

but Tinitial = 0

\epsilon_{initial} - \epsilon _{primary}} = 0.002 - 0.003 = -0.001

\frac{-0.001}{-t_{final}} = 1 \times 10^{-5}(100)^{4}\times 10^{(\frac{-2eV}{8.62\times10^{-5}(\frac{eV}{K} )1073K} )}

solving the above equation,

we get

Tfinal = 2459.82 hr

3 0
3 years ago
Why is it usually better to make a weld in the flat position
ollegr [7]
<h3><u>Answer:</u></h3>

When a welder must certify for their appropriate welder's certifications, all of the samples are basically flat work. Simple tack welds to deep fill welds are required.

<h3><u>Explanation:</u></h3>

If you are welding two pieces of metal together, having the work as flat as possible allows for the best access for the weld to be proper. There are often more times then not that the work will not be in a flat position so if you are really just starting out, your practice welds should be made on flat work to get the skill necessary to weld well in other positions.

7 0
3 years ago
When the psychologist simply records the relationship between two variables...
Wewaii [24]
When a psychologist simply records the relationship between two variables without manipulating them, it is called a correlational study.

The observed relationship does not by itself reveal which variable causes the other. This is the directionally problem. Also, the relationship may be due to a third variable controlling both of the observed variables.
8 0
3 years ago
You wish to design a cantilever beam with a square cross section and length L that can support an end load of F without yielding
koban [17]

Answer:

with a square cross section and length L that can support an end load of F without yielding. You also wish to minimize the amount the beam deflects under load. What is the free variable(s) (other than the material) for this design problem?

a. End load, F.

b. Length, L.

c. Beam thickness, b

d. Deflection, δ

e. Answers b and c.

f. All of the above.

8 0
3 years ago
Two stepped bar is supported at both ends.At the join point of two segments,the force F is applied(downwards).Calculate reactive
nlexa [21]

Answer:

F=200kN

Explanation:

8 0
3 years ago
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