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3 years ago

What is the root when talking about a quadratic equation

Mathematics

2 answers:

Blizzard [7]3 years ago

8 0

The root is the x intercepts or the zeros of the problem

If I were to graph

(x-5)(x+4)=0

We need a number for x which makes this equation 0

The numbers are 5 or -4

These are the x intercepts of the parabola or roots

e-lub [12.9K]3 years ago

6 0

Answer:

The roots of a function are the x-intercepts. By definition, the y-coordinate of points lying on the x-axis is zero. Therefore, to find the roots of a quadratic function, we set f (x) = 0, and solve the equation, ax2 + bx + c = 0.

Step-by-step explanation:

You might be interested in

Order from greatest to least<br> 5 1/2, 5.05, 5 5/9<br> 37/10, 3 2/5, 3 1/4<br> 5/7, 5/6, 5/12

bonufazy [111]

3 2/8, 5/7, 5/6 5/12

Greatest to least: 5 5/9, 5 1/2, 5.05, 37/10, 3 4/10, 3 1/4, 5/6, 5/7, 5/12.

7 0

3 years ago

If f(x) = x + 7 and g(x)=1/x, what is (f o g)(x)?

Black_prince [1.1K]

Answer: 1/x + 7

Step-by-step explanation: you plug the function g(x) into the function f(x) .. substitue g(x) for the x in f(x)

G(x) = 1/x , so you plug that in the x of f(x) and get 1/x + 7

8 0

3 years ago

Write and solve an equation for the following:

IrinaVladis [17]

Answer:

x = (180 - [71 + 9]) ÷ 2

Step-by-step explanation:

71 + 9 = 80

180 - 80 = 100°

100° ÷ 2 = 50°

7 0

2 years ago

Which of the triangles are right triangles?

rewona [7]

Answer:

Number 1 is a right triangle

Number 2 is a right triangle

Number 3 is NOT a right triangle

Number 4 is NOT a right triangle

Step-by-step explanation:

Hope this helps :)

7 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago