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Climate Change

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notsponge [240]3 years ago

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What are two causes of friction

alexira [117]

Answer:

Surface roughness and deformations

Explanation:

Friction is a force that resists the relative motion between two objects or materials. The causes of this resistive force are molecular adhesion, surface roughness, and deformations. Adhesion is the molecular force resulting when two materials are brought into close contact with each other

3 0

3 years ago

Read 2 more answers

Two Forces Of Magnitude 20N Each Are Acting At 30 And 60 degree with xAxis the Y Component Of The Resultant Force Is

vodka [1.7K]

We can find the y-component of the resultant force by adding the y-components of the two 20N forces.

For a force of magnitude F and lying at an angle off the x-axis θ, the y-component of the force is given by:

Fsin(θ)

The magnitude of the two forces is 20N, and they lie at 30° and 60°, so the sum of their y-components, and therefore the y-component of the resultant force, is:

20sin(30°)+20sin(60°)

= 27.3N

5 0

4 years ago

Urgent please help me

Verizon [17]

1433 km

Explanation:

Let g' = the gravitational field strength at an altitude h

$g' = G\dfrac{M_E}{(R_E + h)^2}$

We also know that g at the earth's surface is

$g = G\dfrac{M_E}{R_E^2}$

Since g' = (2/3)g, we can write

$G\dfrac{M_E}{(R_E + h)^2} = \dfrac{2}{3}\left(G\dfrac{M_E}{R_E^2} \right)$

Simplifying the above expression by cancelling out common factors, we get

$(R_E + h)^2 = \dfrac{3}{2} R_E^2$

Taking the square root of both sides, this becomes

$R_E + h = \left(\!\sqrt{\dfrac{3}{2}}\right) R_E$

Solving for h, we get

$h = \left(\!\sqrt{\dfrac{3}{2}} - 1\right) R_E= 0.225(6.371×10^2\:\text{km})$

$\:\:\:\:\:= 1433\:\text{km}$

5 0

3 years ago

As an intern at an engineering firm, you are asked to measure the moment of inertia of a large wheel for rotation about an axis

klio [65]

Hi there!

We can begin by finding the acceleration of the block.

Use the kinematic equation:

$d = v_0t + \frac{1}{2}at^2$

The block starts from rest, so:

$d = \frac{1}{2}at^2\\\\12 = \frac{1}{2}a(4^2)\\\\\frac{24}{16} = a = 1.5 m/s^2$

Now, we can do a summation of forces of the block using Newton's Second Law:

$F = ma = m_bg - T$

mb = mass of the block

T = tension of string

Solve for tension:

$T = m_bg - ma = 8.2(9.8) - 8.2(1.5) = 68.06 N$

Now, we can do a summation of torques for the wheel:

$\Sigma \tau = rF\\\\\Sigma\tau = rT$

Rewrite:

$I\alpha = rT$

We solved that the linear acceleration is 1.5 m/s², so we can solve for the angular acceleration using the following:

$\alpha = a/r\\\\\alpha = 1.5/.42= 3.57 rad/sec^2$

Now, plug in the values into the equation:

$I(3.57) = (0.42)(68.06)\\\\I = (0.42)(68.06)/(3.57) = \boxed{8.00 kgm^2}$

8 0

3 years ago

Convection currents occur when _________ energy transfers between two parts of a fluid

valentinak56 [21]

Answer:

heat

Explanation:

7 0

3 years ago