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trasher [3.6K]
3 years ago
8

(Tennis)

Physics
1 answer:
GrogVix [38]3 years ago
4 0
A) A service winner; the opponent cannot return the serve

B) A tennis stroke made across the body with the back of the hand facing the direction of the stroke

C) Exercising to increase stamina; mostly associated with aerobic activities and cardiovascular health

D) When the ball does not land in the service box

E) Is the absolute range of movement in a joint or series of joints and muscles

F) A stroke done to the right-front of the body (for right-handers), with the racket in a normal position (palm of hand facing opponent)

G) When the service hits the net and lands in a let is played and the server gets another ball

H) A sequence of shots within a point

I) Position facing the net. Used to begin most tennis strokes

J) The way the game begins. Governed by a specific set of rules

K) A tennis stroke that creates a backspin on the ball

L) To exert force on an object using muscles

M) A tennis stroke made across the body with the back of the hand facing the direction of the stroke
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suppose an electrically charged ruler transfers some of its charge by contact to a tiny plastic sphere. will the ruler and the s
poizon [28]

Answer:

Here ball and rod will repel each other as they are of similar charges

Explanation:

As we know that the two charges attract or repel each other by electrostatic force

This force is given as

F = \frac{kq_1q_2}{r^2}

so we know if two charges are similar in nature then they will repel each other and if the two charges are opposite in nature then they will attract each other

So here when rod touch the ball then it transfer its charge to the ball and due to similar charges in ball and rod they both repel each other

5 0
3 years ago
Name three situations in which force is created. describe the cause of the force in each situation
Darina [25.2K]
One situation in which force is created is when an object is moving and a force is created to stop that movement. Second situation is when an object is moving circularly and a force is created to move it towards the middle of the circle. The third situation is when a force is created that goes in the same direction as an object that is in movement.
6 0
3 years ago
A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?
Kobotan [32]

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

5 0
3 years ago
A capacitor with a capacitance of 50µf when connected to a battery of 400 V. The charge and energy stored on it is? a. 0.05 C an
nekit [7.7K]

Answer:

c. 0.02 C and 4 J

Explanation:

Applying,

Q = CV................ Equation 1

Where Q = Charge, C = Capacitance of the capacitor, V = Voltage.

From the question,

Given: C = 50 μF = 50×10⁻⁶ F, V = 400 V

Substitute these values into equation 1

Q = (50×10⁻⁶)(400)

Q = 0.02 C.

Also Applying

E = CV²/2............. Equation 2

Where E = Energy stored.

Therefore,

E = (50×10⁻⁶ )(400²)/2

E = 4 J

Hence the right option is c. 0.02 C and 4 J

3 0
3 years ago
An electron starts from rest in a vacuum, in a region of strong electric field. The electron moves through a potential differenc
Semenov [28]

Answer:

The kinetic energy is  KE  = 5.67*10^{-18} \ J

Explanation:

From the question we are told that

    The potential difference is  \Delta V  =  36 \ volts

       

The potential energy of the end  is mathematically represented as

        PEs  =  - q *  \Delta V

q  is the charge on an electron with a constant value of q =  1.60 *10^{-19} \  C

       substituting values

      PE  =  - 1.60*10^{-19} *  36

      PE  =  -  5.67*10^{- 18} \ J

Now from the law of energy conservation

     The PE_e    =  KEe

Where  KE _e is the potential  energy at the end

 So  

        KE  = 5.67*10^{-18} \ J

The  negative sign is not includes because kinetic energy can not be negative

7 0
3 years ago
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