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Naya [18.7K]
3 years ago
9

Urgent please help me

Physics
1 answer:
Verizon [17]3 years ago
5 0

1433 km

Explanation:

Let g' = the gravitational field strength at an altitude h

g' = G\dfrac{M_E}{(R_E + h)^2}

We also know that g at the earth's surface is

g = G\dfrac{M_E}{R_E^2}

Since g' = (2/3)g, we can write

G\dfrac{M_E}{(R_E + h)^2} = \dfrac{2}{3}\left(G\dfrac{M_E}{R_E^2} \right)

Simplifying the above expression by cancelling out common factors, we get

(R_E + h)^2 = \dfrac{3}{2} R_E^2

Taking the square root of both sides, this becomes

R_E + h = \left(\!\sqrt{\dfrac{3}{2}}\right) R_E

Solving for h, we get

h = \left(\!\sqrt{\dfrac{3}{2}} - 1\right) R_E= 0.225(6.371×10^2\:\text{km})

\:\:\:\:\:= 1433\:\text{km}

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18. Compared to its weight on Earth, a 5 kg object on the moon will weigh A. the same amount. B. less. C. more.
s2008m [1.1K]

Answer:

B. less

Explanation:

acceleration due to gravity on Earth, g = 9.8 m/s²

acceleration due to gravity on Moon, g = 1.6 m/s²

Given mass of the object as, m = 5 kg

Weight of an object is given as, W = mg

                                                         

Weight of the object on Earth, W = 5 x 9.8 = 49 N

Weight of the object on Moon, W = 5 x 1.6 = 8 N

Therefore, the object weighs less on the moon compared to its weight on Earth.

The correct option is "B. less"

8 0
4 years ago
The battery charger for an mp3 player contains a step-down transformer with a turns ratio of 1:38, so that the voltage of 120 v
matrenka [14]
Transformer contains two coils: primary and secondary. They allow change of voltage to lower or higher value. In first case we have step-down and in second case we have step-up transformer.
Formula used for transformer is:\frac{N_{1} }{N_{2}} = \frac{V_{1}}{V_{2}}

Where:N1 = number of turns on primary coilN2 = number of turns on secondary coilV1 = voltage on primary coilV2 = voltage on secondary coil
In a step-down transformer primary coil has more turns than secondary coil. So the ratio 1:38 means that for each turn on secondary coil we have 38 turns on primary coil.
We can solve the equation for V2:V_{2} =  \frac{ V_{1}* N_{2}  }{ N_{1} }  \\  V_{2} =  \frac{ 120* x  }{ 38x} } \\ V_{2} = 3.16V

Secondary coil provides voltage of 3.16V.
7 0
4 years ago
Someone please help me
professor190 [17]
The answer is A. conduction
7 0
3 years ago
An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop the loop maneuver. The acceleration
Natali5045456 [20]

The radius of the loop is 18.9 km

Explanation:

When the airplane is at the top of the loop, the pilot experiences two forces:

  • The force of gravity, acting downward, of magnitude mg
  • The normal reaction exerted by the seat on the pilot, also acting  downward, N

Since the plane is moving in a circular motion, the net force on the pilot must be equal to the centripetal force, therefore we can write:

mg+N = m\frac{v^2}{r}

where

m is the mass of the pilot

g=9.8 m/s^2 is the acceleration of gravity

N is the normal reaction

v = 430 m/s is the speed of the plane

r is the radius of the loop

Here we are told that the pilot feel weightless at the top of the loop: this means that the normal reaction is zero,

N = 0

Therefore the equation becomes

mg=\frac{mv^2}{r}

And so we can find the radius of the loop:

r=\frac{v^2}{g}=\frac{430^2}{9.8}=18.9 \cdot 10^3 m = 18.9 km

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

8 0
3 years ago
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sammy [17]

Answer:

Explanation: ture

8 0
3 years ago
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