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3 years ago

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Mathematics

2 answers:

serious [3.7K]3 years ago

4 0

Answer:

4/5

Step-by-step explanation:

From point (-2,0) to point (3,4).

Rise is 4, Run is 5

krek1111 [17]3 years ago

3 0

Answer:

slope: 4/5

Step-by-step explanation:

(-2,0)&(3,4)

$slope:\frac{y_{2-x_y{2}} }{x_{2-x_x{1} } }$

$=\frac{4-0}{3-(-2)} \\\\=\frac{4}{3+2} \\\\slope: \frac{4}{5}$

hope it helps..

have a great day!!

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In a randomly generated list of numbers from 0 to 8 what is the chance thag each number will occur?

Vitek1552 [10]

Answer:

1/9

Step-by-step explanation:

That's bc there are 9 possible outcomes 0,1,2,3,4,5,6,7,8,

so say an out come is 4, out of 9 chances it was 4 so there is a 1/9 of getting 4

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3 years ago

Write 8.87 as a mixed number and as an improper fraction.<br> Do not try to simplify your answers.

kodGreya [7K]

Answer:

8 87/100 = 887/100

Step-by-step explanation:

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8 87/100 = 887/100

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2 years ago

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279 is 33 1/2 of what amount

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Answer:

33% of 279 is equivalent to multiplying them: 33% × 279.

Step-by-step explanation:

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2 years ago

What set of reflections would carry trapezoid ABCD onto itself? (1 point) Trapezoid ABCD is shown. A is at negative 5, 1. B is a

amid [387]

Answer:

y=x, x axis, y=x, y axis

Step-by-step explanation:

If a point A(x, y) is reflected along the y = x line, the new coordinates would be A'(y, x)

If a point A(x, y) is reflected across the x axis, the new coordinates would be A'(x, -y)

If a point A(x, y) is reflected along the y axis, the new coordinates would be A'(-x, y)

Firstly reflect Trapezoid ABCD along the y = x line to give:

A (-5, 1) ⇒ A'(1, -5). B (-4, 3) ⇒ B'(3, -4). C (-2, 3) ⇒C'(3, -2). D (-1, 1) ⇒ D'(1, -1)

Secondly reflect along the x axis to give:

A'(1, -5)⇒ A"(1,5). B'(3, -4)⇒ B"(3,4), C'(3, -2)⇒C"(3, 2), D'(1, -1) ⇒ D"(1, 1)

Thirdly reflect along the y = x line to give:

A"(1,5) ⇒ A"'(5, 1). B"(3,4) ⇒ B"'(4, 3). C"(3, 2) ⇒ C"'(2, 3). D"(1, 1) ⇒ D"'(1, 1)

Lastly reflect along the y axis to give:

A"'(5, 1) ⇒ A""(-5, 1), B"'(4, 3) ⇒ B""(-4, 3), C"'(2, 3) ⇒ C""(-2, 3), D"'(1, 1) ⇒ D""(-1.1)

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3 years ago

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find

Papessa [141]

Answer:

1) $\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) $\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) $\text{P(at least two girls)}=\frac{1}{2}$

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To Find : The probability of each event.

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

1) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6

$\text{P(at least one boy and one girl)}=\frac{6}{8}$

$\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, GBB=3

$\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

$\text{P(at least two girls)}=\frac{4}{8}$

$\text{P(at least two girls)}=\frac{1}{2}$

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3 years ago

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