Answer:
Option E!
Explanation:
If we were to draw the lewis dot structure for IBr2 -, we would first count the total number of valence electrons ( " available electrons " ). Iodine has 7 valence electrons, and so does Bromine, but as Bromine exists in 2, the total number of valence electrons would be demonstrated below;
Don't forget the negative on the Bromine!
Now go through the procedure below;
1 ) Place Iodine in the middle and draw single bonds to each of the bromine.
2 ) Add three lone pairs on each of the Bromine's
3 ) Now we have 6 electrons left, if we were to exclude the electrons shared in the " single bonds. " This can be placed as three lone pairs on Iodine ( central atom )!
The molecular geometry can't be linear, as there are lone pairs on the atoms. This makes it bent.
Answer : The pH of the solution is, 3.41
Explanation :
First we have to calculate the moles of 
.
Now we have to calculate the value of 
.
The expression used for the calculation of is,
Now put the value of 
in this expression, we get:
The reaction will be:
Initial moles 0.375 0.100 0.375
At eqm. (0.375-0.100) 0 (0.375+0.100)
= 0.275 = 0.475
Now we have to calculate the pH of solution.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[F^-]}{[HF]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BF%5E-%5D%7D%7B%5BHF%5D%7D)
Now put all the given values in this expression, we get:
![pH=3.17+\log [\frac{(\frac{0.475}{1.50})}{(\frac{0.275}{1.50})}]](https://tex.z-dn.net/?f=pH%3D3.17%2B%5Clog%20%5B%5Cfrac%7B%28%5Cfrac%7B0.475%7D%7B1.50%7D%29%7D%7B%28%5Cfrac%7B0.275%7D%7B1.50%7D%29%7D%5D)
Thus, the pH of the solution is, 3.41
Answer:
<h3>B. CH3CH2CH2CH2CH2C1</h3>
Explanation:
I HOPE IT HELPS :)
Answer:
Spot (4) Has evidence that there were waves here at some point. It looks as if the sand/surface debris was moved back and forth, creating this pattern in the sand. Spots (5) and (7) show evidence of water erosion. The smooth edges of both hills mean that water once flowed through that area, carrying little pebbles and rocks that gradually shaped and smoothed those mounds. An example for this would be how there are smooth areas in the Grand Canyon where scientists have concluded that some, if not all, of the Grand Canyon was formed by flowing water. "Rapid uplift, cracking, and surface drainage of receding floodwaters provide both the path and the necessary volume of water to quickly carve out Grand Canyon," says scholars on icr.org.
Explanation:
Water Erosion exists.
