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andre [41]
3 years ago
7

What is the difference between covalent bonding and electrovalent bonding​

Chemistry
1 answer:
Rudiy273 years ago
5 0

Answer:

1 ) Electrovalent compounds are formed by the complete transfer of electrons while covalent compounds are formed by sharing of electrons between 2 atoms.

2) Electrovalent compounds are more soluble in polar solvents like water while covalent compounds are more soluble in non-polar solvents like methane.

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Two very stable compounds, Freon-12 and Freon-14, are used as liquid refrigerants. A Freon-12 molecule consists of one carbon at
Mrrafil [7]
81. There is 1 carbon, 2 chlorine and fluorine atoms in Freon 12. To draw them it forms a cross with C in the middle and Cl and F both on the opposite side. 
     Cl
      l
F - C- F
      l
     Cl

82. Freon-12 and Freon-14 are called halocarbons or just halides. 


6 0
3 years ago
Read 2 more answers
2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo
pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

<u>Chemical reaction involved</u>: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K    (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol)     (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2

<u>To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:</u>

\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}

\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)

\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)

<u>Therefore, the Gibb's free energy change at 37° C (310.15 K): </u><u>ΔG = (-2.45 kJ/mol)</u>

4 0
3 years ago
what is the order of decreasing bond length for a C-C bond composed of the following molecular orbitals?I. sp^3 - sp^3II. sp^2 -
skelet666 [1.2K]

Answer:

The decreasing order of bond length in the carbon - carbon bonds will be:

C-C>C=C>C\equiv C

Explanation:

Bond length is defined as average distance between two nuclei of  bonded atoms in a molecule.Bond length is inversely  proportional to the number of bonds present between two atoms.

\text{Bond length} \propto \frac{1}{\text{Number of bonds}}...[1]

Bond energy is defied as amount of energy required to break apart the bond of 1 mole of molecule into their individual atom. Bond energy is directly proportional to the number of bonds present between two atoms.

\text{Bond Energy} \propto \text{Number of bonds}..[2]

From [1] and [2]:

\text{Bond length} \propto \frac{1}{\text{Bond energy}}

C-C: sp_3 hybridized

C=C: sp_2 hybridized

C\equiv C: sp hybridized

Extent of overlapping of orbitals in these hybridization;

C\equiv C> C=C > C-C

Higher the overlapping of orbital more closer will be both atoms to each other and shorter will be the bond lenght.

So, the decreasing order of bond length in the carbon - carbon bonds will be:

C-C>C=C>C\equiv C

8 0
2 years ago
This type of fatty acid has at least one double bond in the carbon-to-carbon chain and also contains protective qualities
Sloan [31]
There are two general classifications of fatty acids according to their structure: saturated and unsaturated fatty acids. Unsaturated fatty acids are those that contain at least one of either a double or triple bond. Therefore, the answer to this questions is: unsaturated fatty acid. Its function is to protect the organs as a cushion, or as storage area for excess energy.
8 0
3 years ago
Danielle is designing a system to help race cars slow safely and rapidly at her local racetrack. The racetrack is a straight, 1,
xeze [42]

Answer:

The answer is C

Explanation:

She should make the parachutes smaller in order to decrease the drag forces on the car and bring it to a stop 400 meters after crossing the finish line.

3 0
2 years ago
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