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makkiz [27]
3 years ago
5

A gas occupies a volume of 60 L at a temperature of 0.5 K. What will the volume be at 4 K?

Chemistry
1 answer:
Flauer [41]3 years ago
3 0

Answer:

480 L

Explanation:

In order to solve this question, you should be familiar with gas laws. (I will attach a picture showing all of them under my answer.) In this question in particular, however, we only need Charles's Law because we're dealing with temperature and volume.

As we can see, Charles's Law is:

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

or, initial volume over initial temperature equals final volume over final temperature.

In this question, 60 L is our <u>initial volume,</u> and 0.5 K is our <u>initial temperature</u> (K being Kelvin). We are only given 4 K as our <u>final temperature</u>. We are asked to solve for the <u>final volume</u>. Let's set up the equation and solve for V_{2}:

--------------------------------------------------------------------------------------------------------------

(60) / (0.5) = V_{2} / (4)

↓

120 = V_{2} / 4

×4           ×4

↓

V_{2} = 480 L

--------------------------------------------------------------------------------------------------------------

There's our answer! Feel free to comment if you have any questions about my answer :)

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Answer:

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Explanation:

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Answer:

A la izquierda el catión y a la derecha el anión.

Explanation:

¡Hola!

En este caso, y basado en las normas IUPAC para la escritura de las fórmulas moleculares, es necesario primero escribir el catión a la izquerda, seguido del anión a la derecha, tal y como se muestra en los siguientes ejemplos, recordando que el catión es el ion cargado positivamente y el anión, negativamente:

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Answer:

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or the

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or the

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Explanation:

<em>Choose </em><em>your </em><em>answer </em>

<em>brainlilest </em><em>me</em>

<em><u>CARRY </u></em><em><u>ON </u></em><em><u>LEARNING</u></em>

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