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makkiz [27]
3 years ago
5

A gas occupies a volume of 60 L at a temperature of 0.5 K. What will the volume be at 4 K?

Chemistry
1 answer:
Flauer [41]3 years ago
3 0

Answer:

480 L

Explanation:

In order to solve this question, you should be familiar with gas laws. (I will attach a picture showing all of them under my answer.) In this question in particular, however, we only need Charles's Law because we're dealing with temperature and volume.

As we can see, Charles's Law is:

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

or, initial volume over initial temperature equals final volume over final temperature.

In this question, 60 L is our <u>initial volume,</u> and 0.5 K is our <u>initial temperature</u> (K being Kelvin). We are only given 4 K as our <u>final temperature</u>. We are asked to solve for the <u>final volume</u>. Let's set up the equation and solve for V_{2}:

--------------------------------------------------------------------------------------------------------------

(60) / (0.5) = V_{2} / (4)

↓

120 = V_{2} / 4

×4           ×4

↓

V_{2} = 480 L

--------------------------------------------------------------------------------------------------------------

There's our answer! Feel free to comment if you have any questions about my answer :)

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When electrons are added to the outer most shell of a carbon atom what does it form
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When electrons are added to the outermost shell of a carbon atom, it forms an anion.
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3 years ago
How does doubling the volume of solvent affect the concentration of the solution?
Alex17521 [72]

Answer:

Molarity is halved when the volume of solvent is doubled.

Explanation:

Using the dilution equation (volume 1)(molarity 1)=(volume 2)(molarity 2), we can demonstrate the effects of doubling volume.

Suppose the starting volume is 1 L and the starting molarity is 1 M, and doubling the volume would make the final volume 2 L.

Plugging these numbers into the equation, we can figure out the final molarity.

(1 L)(1 M)=(2 L)(X M)

X M= (1 L x 1 M)/(2 L)

X M= 1/2 M

This shows that the molarity is halved when the volume of solvent is doubled.

8 0
3 years ago
To what category of elements does an element belong if it's a poor conductor of electricity
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I would assume NON-METALS

7 0
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How many moles of aluminum are equivalent to 4.816x10^24 atoms? 12.5 8 1.25 0.8
kotegsom [21]

Answer:

8

Explanation:

1 mole = 6.02 × 10²³ atoms

? moles = 4.816 × 10²⁴ atoms.

? Moles = 4.816 × 10²⁴ ÷ 6.02 × 10²³

? Moles = 8 moles

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4 0
3 years ago
Read 2 more answers
A student who stresses too much about his grades has incorrectly named an organic compound 3-propylhexane.
Brums [2.3K]

Answer:

None of these.

The correct answer should be, 4-ethylheptane.

Explanation:

In naming Alkanes, the general rules apply:

I. Identify the longest continuous carbon chain and name it as the root or parent name.

II. Identify any side chains and add their names and positions as a prefix to the parent chain.

III. When there are more than one type of side chain, name them alphabetically.

IV. Use hyphens between numbers and letters and commas between numbers.

V. Number your side chains to obtain the lowest number combinations possible.

For the above question,

first, attempt drawing only the carbon skeleton, of 3-propylhexane thus,

C-C-C-C-C-C

|

C-C-C

The longest continuous carbon chain (numbering from the top right) is 7 carbon atoms, hence, parent or root name is heptane. The 2 carbon atoms (at top left) not numbered make up the alkyl group called ethyl and since they are attached to carbon number 4 of the numbered carbon atoms ( whether the numbering is from top right to bottom right or vice versa ), their position and name should be written as a prefix to the parent name. That is why the organic compound is named, 4-ethylheptane.

Please note that in drawing the carbon skeleton of 3-propylhexane, the name is the same even if you start placing the bottom 3 carbon atoms on the 3rd carbon (top) from the left or from the right because the numbering can start from any side to achieve the lowest number combinations of numbering common Alkanes.

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3 years ago
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